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victus00 [196]
3 years ago
6

Yall know the anwser to this​

Mathematics
1 answer:
Olenka [21]3 years ago
6 0

-1(-1-9)= -1*-10= 10

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One brand of vinegar has a pH of 4.5. Another brand has a pH of 5.0. The equation for the pH of a substance is pH = –log[H+], wh
kiruha [24]

Answer:

2.16 * (10^-5).

Step-by-step explanation:

5 = -log H+

5 = log (1 / H+)

1/ H+ = 10^5

H+ = 10^-5

In a similar fashion  the other brand has H+ of 10^-4.5.

So the difference in hydrogen ion concentration =  10^(-4.5) - 10^(-5)

= 2.16 * (10^-5).

4 0
3 years ago
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2/3p+3. p=3/5<br> What is the Answer to what
Vedmedyk [2.9K]

Step-by-step explanation:

2/3p+3

where p=3/5

substitute p into 2/3p + 3

2/3(3/5) + 3

2/(9/5) + 3

10/9 + 3

10+3)/9

13/9

1 4/9

3 0
3 years ago
Solve for all values of x by factoring.<br> x^2 + 4x – 30 = -3x
vichka [17]

Answer:

{x}^{2}  + 4x - 30 =  - 3x \\{x}^{2}  + 7x - 30 = 0 \\  {x}^{2}  - 3x + 10x - 30 = 0 \\ x(x - 3) + 10(x - 3) = 0 \\ (x - 3)(x + 10) = 0 \\  \boxed{x = 3} \\  \boxed{x =  - 10}

<h3><em><u>x=3 or x=-10</u></em> is the right answer.</h3>

7 0
3 years ago
An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
3 years ago
If the measure of angle 4 is (11 x) degrees and angle 3 is (4 x) degrees, what is the measure of angle 3 in degrees?
GarryVolchara [31]

Answer:

B

Step-by-step explanation:

Angle 4 × Angle 3 = 90

Complementary angles

11x + 4x = 90

15x = 90

x = 6

Angle 3 = 4x = 4(6) = 24°

5 0
3 years ago
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