Answer: a) 0.9961, b) 0.9886
Step-by-step explanation:
Since we have given that
Probability that does not show up = 0.10
Probability that show up = 0.90
Here, we use "Binomial distribution":
n = 125 and p = 0.90
Number of passengers that hold in a flight = 120
a) What is the probability that every passenger who shows up can take the flight?
(b) What is the probability that the flight departs with empty seats?
Hence, a) 0.9961, b) 0.9886
Answer:
There are 2 ways, since we'd chosen 2 fruits
PROBABILITY:
( =
) or
METHOD:
In the 2 fruits we took both of them might be pears either maybe one of them can be a pear. The same is possible with the other fruit.
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Answer:
option (a) Widgets $2,400,000, Gadgets $1,800,000, Targets $5,400,000
Step-by-step explanation:
Data provided in the question:
Allocated estimated overhead = $9,600,000
Expected use of cost drivers for the activity = 800,000 inspections.
Inspections required by Widgets = 200,000
Inspections required by Gadgets = 150,000
Inspections required by Targets = 450,000
Therefore,
Total overhead per activity =
=
= $12 per activity
Thus,
Overhead allocated to Widgets = 200,000 × 12 = $2,400,000
Overhead allocated to Gadgets = 150,000 × 12 = $1,800,000
Overhead allocated to Target = 450,000 × 12 = $5,400,000
Hence, The correct answer is option (a)