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Kisachek [45]
3 years ago
8

Scores on the Wechsler intelligence quotient (IQ) test for adults have a normal probability distribution with a mean score of 10

0 and a standard deviation of 15 points. The US military has minimum enlistment standards at about an IQ score of 85. Based on IQ scores only, what is the probability that a randomly selected adult does not meet US military enlistment standards
Mathematics
1 answer:
bixtya [17]3 years ago
8 0

Answer:

Probability = 0.1587

Step-by-step explanation:

The provided information is:

Let X be the scores of the IQ test for adults that is normally distributed with mean (\mu) = 100 and standard deviation (\sigma) = 15.

Also, US military has minimum IQ score of 85.

Thus, the probability that randomly selected adult does not meet US military enlistment standards is: P(X

The probability can also be written as:

P(X < x) =P(Z

Thus,

P(X

Using the Normal probability table probability of Z = -1 is 0.1587

Thus, the required probability is 0.1587

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2 years ago
Find possible zeroes<br> f(x)=3x^6+4x^3-2x^2+4
larisa [96]

The possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are \mathbf{\pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}

<h3>How to determine the possible zeros?</h3>

The function is given as:

f(x) = 3x^6 + 4x^3 -2x^2 + 4

The leading coefficient of the function is:

p = 3

The constant term is

q = 4

Take the factors of the above terms

p = 1 and 3

q = 1, 2 and 4

The possible zeros are then calculated as:

\mathbf{Zeros = \pm\frac{Factors\ of\ q}{Factors\ of\ p}}

So, we have:

\mathbf{Zeros = \pm\frac{1,2,4}{1,3}}

Expand

\mathbf{Zeros = \pm\frac{1,2,4}{1},\pm\frac{1,2,4}{3}}

Solve

\mathbf{Zeros = \pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}

Hence, the possible zeros of f(x) = 3x^6 + 4x^3 -2x^2 + 4 are \mathbf{\pm\{1,2,4,\frac 13, \frac 23,\frac{4}{3}}\}

Read more about rational root theorem at:

brainly.com/question/9353378

#SPJ1

7 0
2 years ago
Find the gradient of the function g(x,y)= xy at the point (5. - 1). Then sketch the gradient together with the level curve that
guapka [62]

This question is incomplete, the complete question is;

Find the gradient of the function g(x,y)= xy² at the point (5, - 1). Then sketch the gradient together with the level curve that passes through the point.

First find the gradient vector at (5, - 1).

Vg(5,- 1) = [ ]i - [ ]j (Simplify your answers.)

Choose the graph that shows the level curve and the gradient vector at (5, - 1).

options of the sketched graphs are uploaded along this answers

Answer:

Vg(5,- 1) = [ 1 ]i - [ 10 ]j

Option A is the correct graph for this Level

Step-by-step explanation:

Given that;

g(x,y) = xy²

we have to find gradient of this function at ( 5, -1 )

so

Δg(x,y) = dg/dx + dg/dy

d(g)/dx = y² ,       dg/dy = 2gx

therefore

Δg(x,y) = [y²]i + [2yx]j

Δ( 5, -1) = [-1²]i + [2×-1 ×5]j

=Δ(5, -1) = 1i - 10j

[ 1 ]i - [ 10 ]j

Therefore Option A is the correct graph for this Level

3 0
3 years ago
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