The vol. of a cube of side length s is V=s^3.
So, if the side length is 5a+4b, then the volume of the cube is
V(a, b) = (5a+4b)^3. This could, of course, be expanded, using the binomial theorem, but there's no point in doing so.
Answer:
32 cm by 18 cm
16 cm by 36 cm,
48 cm by 12 cm
24 cm by 24 cm
Step-by-step explanation:
<u><em>The complete question is</em></u>
A boy wants to build rectangular cages. He wants all the sides on the base of his cages to beat least 10 cm long.he also wants the base area to equal 576 cm2. The boy needs help to find all the possible lengths and widths for the base of the cages. He used only whole centimeters, with no fractional parts.what are all the possible dimensions for the rectangular base?
we know that
The number 576 decompose in prime factors is the same that write
To find out possible side lengths, multiply different combinations of these prime numbers together (make sure each pair adds up to 10)
3x3=9cm 2x2x2x2x2x2= 64cm ----> is not a combination (one side is not greater than 10)
3x3x2= 18cm 2x2x2x2x2= 32cm
3x3x2x2= 36cm 2x2x2x2= 16cm
3x2x2= 12cm 3x2x2x2x2= 48cm
3x2x2x2= 24cm 3x2x2x2= 24cm
therefore
32 cm by 18 cm
16 cm by 36 cm,
48 cm by 12 cm
24 cm by 24 cm
Answer:
2x + 3x = 5x.
Explanation:
Since they both have the same variable you can just add them so you get 5x.
I hope this helps you :D
The relationship between the reading rate of text and Braille can be modeled in terms of t as B(t) = 0.25t
Let :
Text reading rate = t
<u>Braille reading rate can be expressed in terms of t thus</u> :
<u>Therefore, we could make a proportional relationship table thus </u>:
t = 1
B(t) = 0.25(1) = 0.25
t = 2
B(t) = 0.25(2) = 0.5
t = 3
B(t) = 0.25(3) = 0.75
0.75t = 4
B(t) = 0.25(4) = 1
1 t = 5
B(t) = 0.25(5) = 1.25
Text reading rate, t ; 1 ____ 2 ___ 3 ____ 4 ____ 5
Braille reading rate ;0.25_0.50_0.75 __1.00 __1.25
Therefore, the graph of the relationship between text and braille reading rate is attached below.
Learn more :brainly.com/question/18904995