Answer:
First, find tan A and tan B.
cosA=35 --> sin2A=1−925=1625 --> cosA=±45
cosA=45 because A is in Quadrant I
tanA=sinAcosA=(45)(53)=43.
sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.
sinB=1213 because B is in Quadrant I
tanB=sinBcosB=(513)(1312)=512
Apply the trig identity:
tan(A−B)=tanA−tanB1−tanA.tanB
tanA−tanB=43−512=1112
(1−tanA.tanB)=1−2036=1636=49
tan(A−B)=(1112)(94)=3316
kamina op bolte
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If I understand the question correctly, you can have the same amount of change be two different percentages by having 4 quarters and 100 pennies.
Each quarter is 25%
Each penny is 1%
(am i explaining this right)
13/3= 4.25 because.....
13-12 is 1.
SO:
When you have your problem set up, you have 4, and then a 1 left over. You turn it into a fraction.
Make 4 and 1/4, then put it as a mixed number, 4 1/4
or you can keep dividing by adding a decimal then zeroes and keep solving until you get 4.25 which is equivalent to 4 1/4
C, E, and F have 50 50 chance
Answer:
it will take 3 hours long
