Question

In a geometric sequence, A1 = 0.3 and r=3.Find A12, to the nearest integer

Answer 1

Step-by-step explanation:

We have,

First terms of geometric sequence, a = 0.3

Common ratio, r = 3

It is required to find the 12th term of a GP. The formula of the nth term is given by :

$T_n=ar^{n-1}$

Here, n =12

So,

$T_{12}=0.3\times 3^{12-1}\\\\T_{12}=0.3\times 3^{11}\\\\T_{12}=53144.1$

or

$T_{12}=53144$

So, the 12th term of the GP is 53144.