y < -|x|
replace the letters with the given numbers:
(1,-2) -2<-|1| this is true
(1,-1) -1 <-|1| this is false
(1,0) 0 < -|1| this I false
The answer is (1,-2)
Answer:
options 2,4 and 6 should be correct.
Step-by-step explanation:
Answer:
<em>First even integer: 6</em>
Step-by-step explanation:
<u>Inequalities</u>
Assume x is the first even integer. The next integer is x+2, and the last integer ix x+4.
The condition states that the sum of the first and the second number is 15 less than three times the third. This takes us to the inequality:
Operating:
Subtracting 2 and 2x:
Simplifying:
Solving:
x>5
There are infinitely many solutions. For example, for x=6 (first even number into the solution interval):
First integer: 6
Second integer: 8
Third integer: 10
There are other solutions, like 20,22,24 but the first set is 6,8,10.
6.75 + 3x/8 = 13.25
3x/8 =13.25 - 6.75
3x/8 = 6.5
3X = 6.5 x 8
3x = 52
x= 52/3
So your answer would be 52/3 :)