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kenny6666 [7]
3 years ago
13

A flask containing 9.5 mL of a liquid weight 157.2 g with the liquid in the flask and 148.4 g when empty calculate the density o

f the liquid in grams over milliliters to the correct number of significant digits
Mathematics
1 answer:
agasfer [191]3 years ago
4 0
Density = Mass/Volume
Mass = 152.7 gVolume = 9.5 mL
Since the mass gram correspond to the volume mL, then we can apply the formula:
Density = 152.7/9.5 = 16.074 g/mL (Or kg/L)
You might be interested in
What is the solution to the following system of equations?
kipiarov [429]

Answer:

(0, -6)

Step-by-step explanation:

Given the following systems of linear equations;

3x - 2y = 12 ...... equation 1

16x - 4y = 24 ........ equation 2

We would solve for the solution using the elimination method;

Multiplying eqn 1 by 2, we have;

2 * (3x - 2y = 12)

6x - 4y = 24

16x - 4y = 24

Subtracting the two equations, we have;

(6x - 16x) + (-4y -[-4y]) = (24 - 24)

-10x - 0 = 0

-10x = 0

x = -0/10 = 0

Next, we would find the value of y;

3x - 2y = 12

3(0) - 2y = 12

0 - 2y = 12

-2y = 12

y = -12/2

y = -6

Check:

3x - 2y = 12

3(0) - 2(-6) = 12

0 - (-12) = 12

12 = 12

Note: the options provided for this questions are incorrect or inappropriate.

5 0
3 years ago
Use the discriminant to determine the nature of the roots of the following questions
soldier1979 [14.2K]

Answer:

the function has two distinct real roots.

Step-by-step explanation:

D=b²-4ac    

D<0 No real roots

D=0 One real root

D>0 Two distinct real root.

    (-5)²-4*1*-3

    25+12

    37

Since D is > than 0, the function has two distinct real roots.

6 0
3 years ago
There are 20 machines in a factory. 7 of the machines are defective.
adelina 88 [10]

Answer:

0.1225

Step-by-step explanation:

Given

Number of Machines = 20

Defective Machines = 7

Required

Probability that two selected (with replacement) are defective.

The first step is to define an event that a machine will be defective.

Let M represent the selected machine sis defective.

P(M) = 7/20

Provided that the two selected machines are replaced;

The probability is calculated as thus

P(Both) = P(First Defect) * P(Second Defect)

From tge question, we understand that each selection is replaced before another selection is made.

This means that the probability of first selection and the probability of second selection are independent.

And as such;

P(First Defect) = P (Second Defect) = P(M) = 7/20

So;

P(Both) = P(First Defect) * P(Second Defect)

PBoth) = 7/20 * 7/20

P(Both) = 49/400

P(Both) = 0.1225

Hence, the probability that both choices will be defective machines is 0.1225

4 0
3 years ago
Use the substitution method to solve the system of equations. Choose the correct ordered pair. x + y = 11 -x = -y - 9
suter [353]
x+y=11 \\&#10;-x=-y-9 \\ \\&#10;\hbox{substitute the second equation by -1} \\ \\&#10;x+y=11 \\&#10;x=y+9 \\ \\&#10;\hbox{substitute y+9 for x in the first equation} \\ \\&#10;y+9+y=11 \\&#10;2y=11-9 \\&#10;2y=2 \\&#10;y=\frac{2}{2} \\&#10;y=1 \\ \\&#10;x=y+9 \\&#10;x=1+9 \\&#10;x=10 \\ \\&#10;(x,y)=(10,1)

The answer is B.
5 0
3 years ago
Read 2 more answers
12.73+0.06x=13.48+0.14x
Afina-wow [57]
X= -9.375. 0.06x-0.14x=13.48-12.73. -0.08x=0.75
3 0
3 years ago
Read 2 more answers
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