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2 years ago

How to solve this- (2y-1)^2-4(2y-1) +4

1 answer:

5 0

Step by Step Solution
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STEP
1
:
Equation at the end of step 1

(((2y - 1)2) - 4 • (2y - 1)) + 4
STEP
2
:

Trying to factor by splitting the middle term

2.1 Factoring 4y2-12y+9

The first term is, 4y2 its coefficient is 4 .
The middle term is, -12y its coefficient is -12 .
The last term, "the constant", is +9

Step-1 : Multiply the coefficient of the first term by the constant 4 • 9 = 36

Step-2 : Find two factors of 36 whose sum equals the coefficient of the middle term, which is -12 .

-36 + -1 = -37
-18 + -2 = -20
-12 + -3 = -15
-9 + -4 = -13
-6 + -6 = -12 That's it

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Alika [10]

Answer:

(4,1)

Step-by-step explanation:

x+y=5

x- y=3

Add the equations together to eliminate y

x+y=5

x- y=3

--------------------

2x = 8

Divide each side by 2

2x/2 = 8/2

x = 4

Now we can find y

x+y = 5

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2 years ago

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siniylev [52]

Answer:

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Step-by-step explanation:

Given

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2 years ago

Read 2 more answers

Help!!!!!!!!!!!!!!!!!!!!

lapo4ka [179]

Well... the segment FG = 4x + 3, the segment GH = 7x - 12, now, the

segment FH = FG + GH, those two fellows added up, and we know that FG and GH are both equal halves because G is the midpoint.

thus, FG = GH
or

$\bf 4x+3=7x-12\implies 3+12=7x-4x\implies 15=3x
\\\\\\
\cfrac{15}{3}=x\implies \boxed{5=x}\\\\
-------------------------------\\\\
thus\qquad 
\begin{cases}
\overline{FG}=4x+3\\
4(5)+3\\
23\\
------\\
\overline{GH}=7x-12\\
7(5)-12\\
23
\end{cases}\impliedby equal\ halves
\\\\\\
\overline{FH}=23+23\implies \overline{FH}=46\implies 6y-2=46
\\\\\\
6y=46+2\implies y=\cfrac{48}{6}$

and fairly sure, you know how much that is.

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2 years ago

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maxonik [38]

It would be equal to 110 2/7

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2 years ago

The numerator of a fraction is four less than the denominator. If 17 is added to each.

Mkey [24]

Answer:

x + 13 / x + 17

Step-by-step explanation:

x - 4 / x

x + 13 / x + 17

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1 year ago

How to solve this- (2y-1)^2-4(2y-1) +4​

How to solve this- (2y-1)^2-4(2y-1) +4