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babunello [35]
2 years ago
9

How to solve this- (2y-1)^2-4(2y-1) +4​

Mathematics
1 answer:
Tems11 [23]2 years ago
5 0
Step by Step Solution
More Icon
STEP
1
:
Equation at the end of step 1

(((2y - 1)2) - 4 • (2y - 1)) + 4
STEP
2
:

Trying to factor by splitting the middle term

2.1 Factoring 4y2-12y+9

The first term is, 4y2 its coefficient is 4 .
The middle term is, -12y its coefficient is -12 .
The last term, "the constant", is +9

Step-1 : Multiply the coefficient of the first term by the constant 4 • 9 = 36

Step-2 : Find two factors of 36 whose sum equals the coefficient of the middle term, which is -12 .

-36 + -1 = -37
-18 + -2 = -20
-12 + -3 = -15
-9 + -4 = -13
-6 + -6 = -12 That's it
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Given:

There are given that the parent functions as a cosine function:

Where,

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Explanation:

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f(x)=acos(bx+c)+d

Where,

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Now,

According to the question:

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f(x)=9cos(bx+c)+d

The vertical shift is 11 units down, which means:

f(x)=9cos(bx+c)-11

For period:

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Final answer:

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Step-by-step explanation:

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