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3 years ago

Find the difference 12-20.5

Mathematics

2 answers:

myrzilka [38]3 years ago

7 0

The difference is 8.5

choli [55]3 years ago

4 0

The answer is -8.5. Hope this helps!

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Set up equations and solve.

zavuch27 [327]

One weights 30lbs the other weights 54lbs

3 0

3 years ago

Rani deposited AED 12000 for 3 years at the rate of 5 percent per annum. Calculate the simple interest and amount at the end of

Luda [366]

Answer:

the principal and the amount is 1,800 and 13,800 respectively

Step-by-step explanation:

The computation of the simple interest and amount for the end of the 3rd year is shown below:

Simple interest is

= Principal × rate of interest × time period

= 12,000 × 5% × 3 years

= 1,800

Now the amount is

= 12,000 + 1,800

= 13,800

hence, the principal and the amount is 1,800 and 13,800 respectively

7 0

2 years ago

Suppose that x is the probability that a randomly selected person is left handed. The value (1-x) is the probability that the pe

harina [27]

Answer:

The maximum variance is 250.

Step-by-step explanation:

Consider the provided function.

$V(x)=1000x(1-x)$

$V(x)=1000x-1000x^2$

Differentiate the above function as shown:

$V'(x)=1000-2000x$

The double derivative of the provided function is:

$V''(x)=-2000$

To find maximum variance set first derivative equal to 0.

$1000-2000x=0$

$x=\frac{1}{2}$

The double derivative of the function at $x=\frac{1}{2}$ is less than 0.

Therefore, $x=\frac{1}{2}$ is a point of maximum.

Thus the maximum variance is:

$V(x)=1000(\frac{1}{2})-1000{\frac{1}{2}}^2$

$V(x)=250$

Hence, the maximum variance is 250.

4 0

3 years ago

How many arrangements can be made using 2 letters of the word HYPERBOLAS if no letter is to be used more than once?

alisha [4.7K]

Answer:

90 arrangements

Step-by-step explanation:

Since there are no repititions of letters, there are unique 10 letters in total.

THe number of arrangements would be 2 permutation 10. We need the formula for permutation. That is:

$nPr=\frac{n!}{(n-r)!}\\$

Now, n = 10 [total] and r is 2, so we have:

$nPr=\frac{n!}{(n-r)!}\\\\_{10}P_{2}=\frac{10!}{(10-2)!}\\=\frac{10!}{8!}\\=\frac{10*9*8!}{8!}\\=10*9\\=90$

So, there can be 90 arrangements

3 0

3 years ago

What Is 8÷856....Plz help

otez555 [7]

0.00934579439 Now I'm just waiting until 20 charac- done

4 0

3 years ago