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algol [13]
3 years ago
13

What is the surface area of the right rectangular prism?center your answer in the box.

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
4 0
22in
A= 2 (wl+hl + hw)
Firlakuza [10]3 years ago
3 0
I believe the answer is 22 in^2
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In a right triangle, CosA=0.352 and SinA=0.936 What is the approximate value of tanA?
mr_godi [17]
\tan A=\frac{\sin A}{\cos A}

Proof: \sin\div\cos=\frac{o}h\div\frac{a}h=\frac{o}h\times\frac{h}a=\frac{oh}{ha}=\frac{o}a=\tan

\cos A=0.352,\ \sin A=0.936

\tan A=\frac{0.936}{0.352}

\boxed{\tan A=2.65\overline{90}} <em>(round as needed)</em>
6 0
3 years ago
Read 2 more answers
The radius of a circle is 2 feet. What is the circle's area?
Akimi4 [234]

Answer: 12.57

Step-by-step explanation:

3 0
3 years ago
NEED HELP ASAP!!!
Sergeeva-Olga [200]

Answer:

(b) P(\textrm{Event of getting a 3 in the spinner)}  =  \frac{11}{61}

Step-by-step explanation:

Let E: Event of getting a 3 in the spinner.

So, the number of favorable outcomes  =  11

Total number of outcomes = Number of times the outcomes is {1,2,3,4,5,6}

= {13 +10 +11+16+11}  = { 61}

So, the total number of outcomes = 61

\textrm{Probability of Event E}  = \frac{\textrm{Number of favorable events}}{\textrm{Total number of outcomes}}

So, here P(\textrm{Event of getting a 3 in the spinner)}  =  \frac{11}{61}

3 0
3 years ago
(3/5 - 1/2) divided by 1/2 + 1.6 x (0.3 + 0.42)
MAVERICK [17]
1.202
3/5 and 1/2 can be 6/10 and 5/10. then 0.1/2 is 0.05. for the other part, just plug 0.72 x 1.6 into a calculator.

8 0
3 years ago
The population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t. After 3 hours
Arada [10]

Answer:

The number of bacteria at initial = 187

Step-by-step explanation:

Given that the population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t.

\frac{dN}{dt} = k N

\frac{dN}{N}  = k dt

Integrating both side we get

㏑ N = k t + C ------- (1)

Now given that after 3 hours it is observed that 500 bacteria are present and after 10 hours 5000 bacteria are present.

⇒ ㏑ 500 = 3 k + C -------- (2)

⇒ ㏑ 5000 = 10 k + C ------ (3)

⇒ ㏑ 5000 -  ㏑ 500 = 7 k

⇒ ㏑\frac{5000}{500} = 7 k

⇒  ㏑ 10 = 7 k

⇒ k = 0.329

Put this value of k in equation (2),

⇒ ㏑ 500 = 3 × 0.329 + C

⇒ C = 5.23

Put this value of C in equation 1 we get,

⇒ ㏑ N = k t + 5.23

Initially when t = 0 , then

⇒ ㏑ N = 5.23

⇒ N =  187

Thus the number of bacteria at initial = 187

8 0
3 years ago
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