Cot theta - cosec theta = P , then cot theta + cosec theta =
1 answer:
Recall
or, $\csc^2\theta-\cot^2\theta=1 \implies (\csc\theta+\cot\theta)(\csc\theta-\cot\theta)=1$
Now, $\cot \theta - \csc \theta = P$
$\implies (-P)(\csc\theta+\cot\theta)=1$
or $(\csc\theta+\cot\theta)=-\frac{1}{P}$
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