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serg [7]
3 years ago
5

Calculate the ph of a buffer that is 0.13m in lactic acid and 0.10m in sodium lactate.

Chemistry
1 answer:
Alona [7]3 years ago
3 0
According to Henderson–Hasselbalch Equation,

                                       pH  =  pKa + log [Lactate] / [Lactic Acid]
As,
      Ka of Lactic Acid  =  1.38 × 10⁻⁴

           pKa  = -log Ka
           pKa  = -log 1.38 × 10⁻⁴
           pKa  =  3.86
So,
                                  pH  =  3.86 + log [0.10] / [0.13]

                                  pH  =  4.74 + log 0.769

                                  pH  =  4.74 - 0.11

                                  pH  =  4.63
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Why do you think the process to create a protected area takes so long?
Paladinen [302]

The process to create a protected area takes a long time because there's numerous things that have to be taken in account and sorted out before the area gets that kind of legal status.

Usually there's people living in the area that is supposed to be protected, though it is mostly small settlements. The people living there are connected with that area, use the resources, and their lives are largely based and dependent on it. In order for any problems to be avoided, these people should all be educated, deals to be made with them, and properly negotiated so that the area wouldn't have any damage, but also them to be able to sustain themselves.

The boundaries of the area are also complicated, it it takes time to sort out what parts should be included and what not. Basically to set the priorities.

People should be employed to protect and take care of the area, so they have to undergo a training, education, and to get familiar with it.

The legalization of the area as such can sometimes too make problems and take some time.

4 0
3 years ago
In the reaction 4Al+3O2→_Al2O3 , what coefficient should be placed in front of the Al2 to balance the reaction?
nika2105 [10]

Sorry I came a lil late,

The answer to your question is, 2.

Hope this helps! :)

6 0
4 years ago
Read 2 more answers
fills a 500.mL flask with 3.6atm of carbon monoxide gas and 1.2atm of water vapor. When the mixture has come to equilibrium she
enot [183]

Answer:

The answer to the question is

The pressure of carbon dioxide after equilibrium is reached the second time is 0.27 atm rounded to 2 significant digits

Explanation:

To solve the question, we note that the mole ratio of the constituent is proportional to their partial pressure

At the first trial the mixture contains

3.6 atm CO

1.2 atm H₂O (g)

Total pressure = 3.6+1.2= 4.8 atm

which gives

3.36 atm CO

0.96 atm H₂O (g)

0.24 atm H₂ (g)

That is

CO+H₂O→CO(g)+H₂ (g)

therefore the mixture contained

0.24 atm CO₂ and the total pressure =

3.36+0.96+0.24+0.24 = 4.8 atm

when an extra 1.8 atm of CO is added we get Increase in the mole fraction of CO we have one mole of CO produces one mole of H₂

At equilibrium we have 0.24*0.24/(3.36*0.96) = 0.017857

adding 1.8 atm CO gives 4.46 atm hence we have

 (0.24+x)(0.24+x)/(4.46-x)(0.96-x) = 0.017857

which gives x = 0.031 atm or x = -0.6183 atm

Dealing with only the positive values we have the pressure of carbon dioxide = 0.24+0.03 = 0.27 atm

7 0
3 years ago
Calculate 4 Srxn for this equation. Round to the
masya89 [10]

Answer:

On edge nuity, it is 79.

Explanation:

Please read the explanation.

Since u have no coefficients, this problem is super easy.

You just add your products, 115.5+69.91 = 185.41

Then add your reactants: 49.8+56.5= 106.3

Then subtract your reactants from your product and round to the nearest whole number.

106.3-185.41=79

It's really easy. Once u understand it, you can do any problem like this. If there is coefficients, just multiply the coefficient by the amount given to you in the problem.

7 0
3 years ago
Calculate the distance that a man walked if it took him 42 seconds to walk at a speed of 3m/s.
Hitman42 [59]

Answer:

126 m

Explanation:

Distance=time*speed➡42*3=126m.

7 0
3 years ago
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