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serg [7]
3 years ago
5

Calculate the ph of a buffer that is 0.13m in lactic acid and 0.10m in sodium lactate.

Chemistry
1 answer:
Alona [7]3 years ago
3 0
According to Henderson–Hasselbalch Equation,

                                       pH  =  pKa + log [Lactate] / [Lactic Acid]
As,
      Ka of Lactic Acid  =  1.38 × 10⁻⁴

           pKa  = -log Ka
           pKa  = -log 1.38 × 10⁻⁴
           pKa  =  3.86
So,
                                  pH  =  3.86 + log [0.10] / [0.13]

                                  pH  =  4.74 + log 0.769

                                  pH  =  4.74 - 0.11

                                  pH  =  4.63
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Find the mass in grams of 3.00 x 1023 molecules of F2
LUCKY_DIMON [66]
<h3>Answer:</h3>

18.9 g F₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

3.00 × 10²³ molecules F₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of F₂ (Diatomic) - 38.00 g/mol

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.00 \cdot 10^{23} \ molecules \ F_2(\frac{1 \ mol \ F_2}{6.022 \cdot 10^{23} \ molecules \ F_2})(\frac{38.00 \ g \ F_2}{1 \ mol F_2})
  2. Multiply:                                                                                                             \displaystyle 18.9306 \ g \ F_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

18.9306 g F₂ ≈ 18.9 g F₂

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