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Oksanka [162]
3 years ago
7

blood plasma for average adults has a volume of 3100mL. if the density of plasma is 1.020 g/mL, what mass of plasma is in the av

erage adult?
Chemistry
1 answer:
Gnoma [55]3 years ago
4 0

Answer:

The volume of blood plasma in adults is 3.1 L. it's density is 1.03 g/cm3.

Explanation:

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What is the value for AG at 5000 K if AH = -220 kJ/mol and S= -0.05 kJ/(mol-K)?
Serhud [2]

Answer:

C. 30 kJ

Explanation:

Hello there!

In this case, in agreement to the thermodynamic definition of the Gibbs free energy, in terms of enthalpy of entropy:

\Delta G= \Delta H-T\Delta S

It is possible to calculate the required G by plugging in the given entropy and enthalpy as shown below:

\Delta G=-220kJ/mol-5000K*-0.05kJ/mol*K\\\\\Delta G=30kJ/mol

Therefore, the answer is C. 30 kJ .

Best regards!

4 0
2 years ago
Using the following equation 5KNO2+2KMnO4+3H2SO4=5KNO3+2MnSO4+K2SO4+3H20. Starting with 2.47 grams of KNO2 and excess KMnO4 how
Aleonysh [2.5K]

Given equation : 5KNO_{2} + 2KMnO_{4} + 3H_{2}SO_{4}\rightarrow 5KNO_{3} + 2MnSO_{4} + K_{2}SO_{4} + 3H_{2}O

Given information = 2.47 grams KNO2 and excess KMnO4 and we need to find grams of water (H2O).

Since KMnO4 is in excess, so grams of water(H2O) can be calculated using grams of KNO2 with the help of stoichiometry.

To find grams of water(H2O) from grams of KNO2 , we need to follow three steps.

Step 1. Convert 2.47 grams of KNO2 to moles of KNO2.

Moles = \frac{grams}{molar mass}

Molar mass of KNO2 = 85.10 g/mol

Moles = 2.47 gram KNO2\times \frac{1 mol KNO2}{85.10 gram KNO2}

Moles = 0.0290 mol KNO2

Step 2. Convert moles of KNO2 to moles of H2O using mole ratio.

Mole ratio are the coefficient present in front of the compound in the balanced equation.

Mole ratio of KNO2 : H2O is 5 : 3 (5 coefficient of KNO2 and 3 coefficient of H2O)

0.0290 mol KNO2\times \frac{3 mol H2O}{5 mol KNO2}

Mole = 0.0174 mol H2O

Step 3. Convert mole of H2O to grams of H2O

Grams = Moles X molar mass

Molar mass of H2O = 18.00 g/mol

Grams = 0.0174 mol H2O\times \frac{18 g H2O}{1 mol H2O}

Grams of water = 0.313 grams H2O

Summary : The above three steps can also be done in a singe setup as shown below.

2.47 gram KNO2\times \frac{(1 mol KNO2)}{(85.10 gram KNO2)}\times \frac{(3 mol H2O)}{(5 mol KNO2)}\times \frac{(18.00 gram H2O)}{(1mol H2O)}

In the above setup similar units get cancelled out and we will get grams of H2O as 0.313 grams water (H2O)

8 0
3 years ago
A sample of an ideal gas at 1.00 atm and a volume of 1.84 L was placed in a weighted balloon and dropped into the ocean. As the
Inessa05 [86]

Answer:

0.0613 L

Explanation:

Given data

  • Initial pressure (P₁): 1.00 atm
  • Initial volume (V₁): 1.84 L
  • Final pressure (P₂): 30.0 atm
  • Final volume (V₂): ?

Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 1.00 atm × 1.84 L / 30.0 atm

V₂ = 0.0613 L

6 0
3 years ago
Examine the following equations.
Alex

Answer: (A) and (D)

Options (A) and (D) represent beta decay.

Explanation:

It is very simple to find  beta decay in a nuclear reaction. In beta decay , neutron breaks down into a proton and an electron. After that electron is emitted from the nucleus,while proton remains inside nucleus. The resulting daughter nuclei will have one more proton and one less neutron.

8 0
3 years ago
Read 2 more answers
What is Sublimation? ​
Stolb23 [73]

Answer:

When a solid turns to a gas.

Explanation:

4 0
3 years ago
Read 2 more answers
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