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sukhopar [10]
3 years ago
11

What did dalton suggest that the structure of the atom looked like?

Chemistry
1 answer:
dedylja [7]3 years ago
5 0
Solid indistructible units that are really small really
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The nuclide Rn-204 is the daughter nuclide resulting from the α decay of what
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Explanation:

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Calculate the number of molecules present in 11 moles of H2O.
DedPeter [7]

Answer:

11 \times 6.022 \times  {10}^{23}  \\  = 66.242\times  {10}^{23} \: of \:  \\ water \: molecules

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According to the kinetic theory, gases consist of particles that
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in constant, random motion. They continue in a straight line until they collide with something—usually each other or the walls of their container. Particles are point masses with no volume.

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3 years ago
Read 2 more answers
Cis-platin is a chlorine-containing chemotherapy agent with the formula pt(nh3)2cl2. What is the mass of one mole of cis-platin?
marishachu [46]

Cis-platin is a chemotherapy agent used to treat and kill cancerous cells in patients. One mole of cis-platin has a mass of 300.06 grams/mol. Thus, option B is correct.

<h3>What is a chemotherapy agent?</h3>

A chemotherapy agent is an alkylating agent that is used to treat cancer and is given to reduce the infection or to relieve the symptoms. Cis-platin (Pt(NH₃)₂Cl₂) is one of the chemotherapy agents that treat lung, ovarian, and neck cancer, etc.

The mass of one mole of Cis-platin is calculated as,

Moles = mass ÷ molar mass

Where,

Moles = 1 mole

The molar mass of (Pt(NH₃)₂Cl₂) is calculated as,

195.06 g/mole + 2(17g/mole) + (35.5)2 = 300.06 grams

Substituting values to calculate mass:

Mass = Molar mass × moles

= 300. 06  × 1

= 300.06 grams/mol

Therefore, option B. 300.06 gm/mol is the mass of Cis-platin.

Learn more about chemotherapy agents here:

brainly.com/question/14260402

#SPJ4

Your question is incomplete, but most probably your full question was, Cis-platin is a chlorine-containing chemotherapy agent with the formula pt(nh3)2cl2. What is the mass of one mole of cis-platin?

  • 488.91 g/mol
  • 300.06 g/mol
  • 492.37 g/mol
  • 283.02 g/mol
  • 2860.5 g/mol
8 0
2 years ago
3.15.8 cm3 of H2SO4 completely neutralised 20 cm3 of NaOH. The NaOH was 1.5 mol/dm3.
Furkat [3]

Answer:

Molarity = 0.95 mol/dm³

Explanation:

Given data:

Volume of H₂SO₄ = 15.8 cm³

Volume of NaOH = 20 cm³

Concentration of NaOH = 1.5 mol/dm³

Concentration of H₂SO₄ = ?

Solution:

Chemical equation:

NaOH + H₂SO₄      →          Na₂SO₄ + H₂O

First of all we will calculate the number of moles of NaOH and for that we will convert the units first,

Volume = 20 cm³/1000 = 0.02 L

Concentration of NaOH = 1.5 mol/dm³

1 mol/dm³ = 1 mol/L

Concentration of NaOH = 1.5 mol/L

Number of moles of NaOH:

Molarity = number of moles / volume in L

1.5 M = number of moles / 0.02 L

Number of moles = 1.5 M ×0.02 L

Number of moles = 0.03 mol

Now we will compare the moles of NaOH and H₂SO₄

                     NaOH           :        H₂SO₄

                         2               :           1

                     0.03             :        1/2×0.03 = 0.015 mol

Concentration of H₂SO₄:

Volume of H₂SO₄:

15.8 cm³/1000 = 0.0158 L

Molarity = number of moles / volume in L

Molarity = 0.015 mol / 0.0158 L

Molarity = 0.95 mol/L

1 mol/L = 1 mol/dm³

Molarity = 0.95 mol/dm³

6 0
3 years ago
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