Answer:
Step-by-step explanation:
Solution by substitution method
3x+5y=7
and 4x-y=5
Suppose,
3x+5y=7→(1)
and 4x-y=5→(2)
Taking equation (2), we have
4x-y=5
⇒y=4x-5→(3)
Putting y=4x-5 in equation (1), we get
3x+5y=7
⇒3x+5(4x-5)=7
⇒3x+20x-25=7
⇒23x-25=7
⇒23x=7+25
⇒23x=32
⇒x=32/23
→(4)
Now, Putting x=32/23
in equation (3), we get
y=4x-5
⇒y=4(32/23)-5
⇒y=(128-115)/23
⇒y=13/23
∴y=13/23 and x=32/23
9514 1404 393
Answer:
A. The equation represents a linear function because the equation is in the form y = mx + b
Step-by-step explanation:
A linear function does not have to be in the form y = mx + b, but if a function is in that form, it is a linear function.
choice A is appropriate
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A function may have two variables, x and y, and not be a linear function. For example, y = x² is not a linear function. The fact that it has two variables is not what makes it linear.
The answer is y = -1/3x + 2
Because the y intersect is located at (0,2) we know that the b value in the formula y=mx + b is 2 and using rise over run we determine the slope to be -1/3
9514 1404 393
Answer:
23, 49
Step-by-step explanation:
Let s represent the smaller of the two numbers. Then the larger is s+26, and the sum is ...
s + (s+26) = 72
2s = 72 -26
s = (72 -26)/2 = 23
Then the larger number is
s +26 = 49
The two numbers are 23 and 49.
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The reason we wrote the solution this way is to show you that the smaller number is half the difference between the given sum (72) and difference (26). This is the generic solution to a "sum and difference" problem. The smaller number is always half the difference of the give sum and difference. (Similarly, the larger is always half the sum of the given sum and difference.)
That is, the two numbers are always half the sum ± half the difference:
72/2 ± 26/2 = {36+13, 36-13} = {49, 23}
