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Harlamova29_29 [7]
3 years ago
12

Alexander was given a gift card for a coffee shop. Each morning, alexander uses the card to buy one cup of coffee. Each cup of c

offee costs $1.50 and after buying 4 cups of coffee , the card had a $9 remaining balance. Write an equation for A in terms of x
Mathematics
1 answer:
german3 years ago
7 0

Answer:

A = (cost per cup of coffee * number of cups) + balance

$15

Step-by-step explanation:

Given that :

Cost per cup of coffee = $1.50

Number of cups purchased = 4

Balance on card = $9

Let A = worth of gift card

A = (cost per cup of coffee * number of cups) + balance

A = (1.50 * 4) + 9

A = 6 + 9

A = $15

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3 years ago
Please answer the question ​
Lady bird [3.3K]

Answer:

the first one is

+2 +4 + 8 + 16 +32

he multiply by 2 every time he add numbers so its 65

the second one he make this

-8 -4 -2 -1

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so its 5

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Step-by-step explanation:

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6 0
3 years ago
The given line segment has a midpoint at (3, 1).
Katena32 [7]

Answer:

y=\frac{1}{3}x

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through (x_1,y_1)\ and\ (x_2,y_2) is:

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}.

Therefore the line passing through (2, 4) and (4, -2) has an equation:

\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

m_1m_2=-1.

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

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Since it is the  perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x

the equation, in slope-intercept form, of the perpendicular bisector of the given line segment is y=\frac{1}{3}x

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olga2289 [7]

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The x-intercept is the point on your line where y=0. On this line, the x-intercept is the point (125,0) (x,y)

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