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emmasim [6.3K]
3 years ago
13

The volume of a pyramid varies jointly with the base area of the pyramid and its height. The volume of one pyramid is 35 cubic i

nches when its base area is 15 square inches and its height is 7 inches. What is the volume of a pyramid with a base area of 36 square inches and a height of 5 inches?
Mathematics
1 answer:
Alla [95]3 years ago
6 0
You first might want to divide 36 by 3, giving you 12. Multiply 12 by 5, which results in your answer of 60in^3. The equation for this is V = 1/3(blh)
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Hi quick whats 18 x 1.25 <br> step by step !!
Ivan

Answer:

22.5

Step-by-step explanation:

125

x 18

---------

1. first set up your problem

2 4

125

x 18

------

1000

2. next multiply the 8 by 5 getting 40, drop the 0 anf move the 4 to the top above 2.

3. multiply 8 by 2 getting 16, then add the 4 you have ontop of the 2 to the 16 getting 20. Drop the 0 and bring the 2 over and place it above the one.

4. multiply 8 by 1 getting 8 then add the 2 above the 1 to 8 getting 10. Then put the ten infront of the tw zeros. 1000

125

x 18

--------

1000

0

Next add a 0 as a place filler under the 0 at the end.

125

x 18

-------

1000

1250

Then multiply the 1 by 5, then 1 by 2, then finnaly 1 by 1, getting you 1250.

1000

+1250

add together

getting 2250

then move 2 decimal places over to get 22.5

3 0
3 years ago
Use a drawing of counters to show 5 and then +7
Rama09 [41]

red red red red red yellow yellow yellow yellow yellow yellow

hope this helps :)

3 0
3 years ago
Suppose that the number of drivers who travel between a particular origin and destination during a designated time period has a
andrew11 [14]

Answer:

Step-by-step explanation:

Given that the number of drivers who travel between a particular origin and destination during a designated time period has a Poisson distribution with parameter μ = 20 (suggested in the article "Dynamic Ride Sharing: Theory and Practice"†).

a) P(X\leq 15) = 0.1565=0.157

b) P(X>26) =1-F(26)\\= 1-0.9221\\=0.0779=0.078

c) P(15\leq x\leq 26)\\=F(26)-F(14)\\=0.9221-0.1049\\=0.8172=0.817

d) 2 std dev = 2(20) =40

Hence 2 std deviation means

20-40, 20+40

i.e. (0,60)

P(0

5 0
3 years ago
What is the constant of vanation,<br>of the line y = for through (3.18) and (5,30)?​
Naily [24]

the constant of variation or namely its slope will be

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{18})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{30}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{30-18}{5-3}\implies \cfrac{12}{2}\implies 6

8 0
3 years ago
1500 soldiers arrive at a training camp. A few soldiers desert the camp. The drill sergeants divide the remaining soldiers into
iren [92.7K]

Answer:

The number of deserters is 34.

Step-by-step explanation:

We have to calculate the number of desertors in a group of 1500 soldiers.

The sergeant divides in groups of different numbers and count the lefts over.

If he divide in groups of 5, he has on left over. The amount of soldiers grouped has to end in 5 or 0, so the total amount of soldiers has to end in 1 or 6.

If he divide in groups of 7, there are three left over. If we take 3, the number of soldiers gruoped in 7 has to end in 8 or 3. The only numbers bigger than 1400 that end in 8 or 3 and have 7 as common divider are 1428 and 1463.

If we add the 3 soldiers left over, we have 1431 and 1466 as the only possible amount of soldiers applying to the two conditions stated until now.

If he divide in groups of 11, there are three left over. We can test with the 2 numbers we stay:

(1431-3)/11=1428/11=129.82\\\\(1466-3)/11=1463/11=133

As only 1466 gives a possible result (no decimals), this is the amount of soldiers left.

The deserters are 34:

D=1500-1466=34

6 0
3 years ago
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