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IrinaK [193]
3 years ago
15

What is the taxidistance between (17,3) and (5,13) ?

Mathematics
1 answer:
dmitriy555 [2]3 years ago
3 0
<span>|17-5| + |3-13| = 12 + 10 = 22 </span>
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Compare the functions shown below:<br><br> Which function has the greatest maximum y-value?
solmaris [256]
Answer: It's a tie between f(x) and h(x). Both have the same max of y = 3

The highest point shown on the graph of f(x) is at (x,y) = (pi,3). The y value here is y = 3.

For h(x), the max occurs when cosine is at its largest: when cos(x) = 1. 
So,
h(x) = 2*cos(x)+1
turns into
h(x) = 2*1+1
h(x) = 2+1
h(x) = 3
showing that h(x) maxes out at y = 3 as well

--------------------------------

Note: g(x) has all of its y values smaller than 0, so there's no way it can have a max y value larger than y = 3. See the attached image to see what this graph would look like if you plotted the 7 points. A parabola seems to form. Note how point D = (-3, -2) is the highest point for g(x). So the max for g(x) is y = -2

3 0
2 years ago
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Consider the function f(x) = 49.5(0.82).
slavikrds [6]

Answer:

1. Exponential decay

2. 18%

Step-by-step explanation:

3 0
3 years ago
2.6 more than the quotient of h and 3 is w
dangina [55]
<span>So, "2.5 more than the quotient of h and 3 is w" becomes 2.5 + h/3 = w. </span>
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3 years ago
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Question 6(Multiple Choice Worth 1 points)
Dafna11 [192]

Answer:

O The value of f(2) is smaller than the value of f(1).

Step-by-step explanation:

First, let's solve for both. When the problem says f(1) or f(2), this just means that the x value is equal to that. So:
f(1) = -5(1)^2 + 2(1) + 9 = 6
f(2) = -5(2)^2 + 2(2) + 9 = -7
Since f(1) = 6 and f(2) = -7, we know that f(1) is greater than f(2). Therefore, the value of f(2) is smaller than the value of f(1)

3 0
2 years ago
Please help radical expression dividing
77julia77 [94]
\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad &#10;\begin{cases}&#10;63=3\cdot 3\cdot 7\\&#10;6=2\cdot 3&#10;\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}&#10;\\\\\\&#10;\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}

\bf \textit{now, rationalizing the denominator}\\\\&#10;\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}&#10;\\\\\\&#10;\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.
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3 years ago
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