Obtain the sample standard deviation 9, 10, 11, 12 ,13 ,14 ,15 ,16 ,17

a cooler contains 50 bottles; 30 bottles of water, which 8 are lemon flavored and 20 bottles of tea, of which 5 are lemon flavor

xenn [34]

Answer:

The required probability is $\dfrac{13}{50}$

Step-by-step explanation:

Total number of bottles = 50

Total number of water bottles = 30

Total number of lemon flavored water bottles = 8

Total number of tea bottles = 20

Total number of lemon flavored tea bottles = 5

Probability of selecting a lemon flavored water bottle = Probability of selecting a water bottle $\times$ Probability of selecting a lemon bottle out of water bottles.

Probability of selecting a lemon flavored tea bottle = Probability of selecting a tea bottle $\times$ Probability of selecting a lemon bottle out of tea bottles.

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

Probability of selecting a water bottle:

$\dfrac{30}{50} = \dfrac{3}{5}$

Probability of selecting a lemon flavored bottle from water bottle:

$\dfrac{8}{30}$

Probability of selecting a lemon flavored water bottle = P(A)

$\dfrac{3}{5} \times \dfrac{8}{30} = \dfrac{4}{25}$

Probability of selecting a tea bottle:

$\dfrac{20}{50} = \dfrac{2}{5}$

Probability of selecting a lemon flavored bottle from tea bottle:

$\dfrac{5}{20} = \dfrac{1}{4}$

Probability of selecting a lemon flavored tea bottle = P(B)

$\dfrac{2}{5} \times \dfrac{1}{4} = \dfrac{1}{10}$

The required probability is:

P(A) + P(B):

$\dfrac{4}{25} + \dfrac{1}{10}\\\Rightarrow \dfrac{8+5}{50}\\\Rightarrow \dfrac{13}{50}$

8 0

3 years ago

Please help fast, thanks.

Sav [38]

Answer:

b > 100

Step-by-step explanation:

3 0

2 years ago

2x - 2y = 10 and x + 2y = 11

Rufina [12.5K]

Answer:

Step-by-step explanation:

What are u asking for x or y

7 0

3 years ago

A flower using 1 line segment and 8 rays

djverab [1.8K]

Answer:

Use the one line segment as flower stem and use the 8 rays as petals.

7 0

3 years ago

In a genetics experiment on peas, one sample of offspring contained 376green peas and 150yellow peas. Based on those results,

ivanzaharov [21]

Answer:

1a. p0= 0.714

1b The result is not reasonably close to the value of 3/4 that was expected

Step-by-step explanation:

1a.Since One sample of offspring contained 376 green peas and 150 yellow peas therefore the probability of getting an offspring pea that is green will be:

Green pea/(Green pea+ Yellow pea)

p0= 376 /(376+150)

p0=376/526

Probability of getting Green pea = 0.714

1b.The result is not reasonably close to the value of 3/4 that was expected.

4 0

3 years ago