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amm1812
4 years ago
14

What is the answer i ca fine it

Mathematics
1 answer:
Jlenok [28]4 years ago
4 0
The cylinder is 6 times bigger
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What is the surface area of the right trapezoidal prism? To receive credit, you must show the work used to arrive at a final ans
julia-pushkina [17]

Answer:

210 cm²

Step-by-step explanation:

The net of the right trapezoidal prism consists of 2 trapezoid base and four rectangles.

Surface area of the trapezoidal prism = 2(area of trapezoid base) + area of the 4 rectangles

✔️Area of the 2 trapezoid bases:

Area = 2(½(a + b)×h)

Where,

a = 7 cm

b = 11 cm

h = 3 cm

Plug in the values

Area = 2(½(7 + 11)×3)

= (18 × 3)

Area of the 2 trapezoid bases = 54 cm²

✔️Area of Rectangle 1:

Length = 6 cm

Width = 3 cm

Area = 6 × 3 = 18 cm²

✔️Area of Rectangle 2:

Length = 7 cm

Width = 6 cm

Area = 7 × 6 = 42 cm²

✔️Area of Rectangle 3:

Length = 6 cm

Width = 5 cm

Area = 6 × 5 = 30 cm²

✔️Area of Rectangle 4:

Length = 11 cm

Width = 6 cm

Area = 11 × 6 = 66 cm²

✅Surface area of the trapezoidal prism = 54 + 18 + 42 + 30 + 66 = 210 cm²

7 0
3 years ago
What is the diameter, circumference, and area of a circle that has the radius of 7?
user100 [1]

Answer:

the diameter is: 14

the circumference is: C≈43.98

the area is: A≈153.94

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Write the inequality shown in the graph below:
love history [14]

Answer:

y < 4

Step-by-step explanation:

Since the line is dotted, it will be either greater than or less than depending on if it is shaded above or below. It's "y" because the line crosses the y axis, not the x axis.

5 0
4 years ago
Write a real word problem that can be represented by the equation a - 6 = 15
chubhunter [2.5K]

Answer: your friend is trying to find out how many canys are in a box(a) and he gives you 6 and has 15 left

Step-by-step explanation:

3 0
3 years ago
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Use the substitution method to solve the system of equations. Choose the correct ordered pair. x + y = 11 -x = -y - 9
suter [353]
x+y=11 \\&#10;-x=-y-9 \\ \\&#10;\hbox{substitute the second equation by -1} \\ \\&#10;x+y=11 \\&#10;x=y+9 \\ \\&#10;\hbox{substitute y+9 for x in the first equation} \\ \\&#10;y+9+y=11 \\&#10;2y=11-9 \\&#10;2y=2 \\&#10;y=\frac{2}{2} \\&#10;y=1 \\ \\&#10;x=y+9 \\&#10;x=1+9 \\&#10;x=10 \\ \\&#10;(x,y)=(10,1)

The answer is B.
5 0
3 years ago
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