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3 years ago

What is the volume of this prism?

Mathematics

1 answer:

Mars2501 [29]3 years ago

3 0

Answer:

The answer is 42ft ^3 (42 ft units cubed)

Step-by-step explanation:

To find the volume for a rectangular prism, first of all you need to know the formula. The formula is V=lwh (volume= length x width x height)

The formmula for this problem is V= 7ft x 2ft x 3ft= 42ft

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Yooo someone

natita [175]

Answer:

39 sq cm

Step-by-step explanation:

Ok. Since ΔAED is isosceles, then the height of the trapezoid is 3 cm

One base is 16 and the other base is 16 - 3 - 3 = 10.

A = 1/2 h( $b_{1}$ + $b_{2}$ ) where $b_{1}$ and $b_{2}$ are lengths of the bases

A = 1/2(3)(10 + 16)

= 1/2(3)(26)

= 39 sq cm

8 0

3 years ago

This diagram of a rectangular city park was drawn using a scale of 1 centimeter to 20 meters

I am Lyosha [343]

Answer:

Scale factor for the drawing from actual park = $\frac{1}{20}$

Area of the actual park = 1200 cm²

Step-by-step explanation:

Length of the rectangular city park = 5 cm

Width of the rectangular park = 6 cm

Using scale factor 1 cm = 20 meters

Scale factor = $\frac{\text{length of the park in drawing}}{\text{Actual length of park}}=\frac{1}{20}$

$\frac{5}{\text{Actual length of park}}=\frac{1}{20}$

Actual length = 5 × 20 = 100 meters

Actual width = 6 × 20 = 120 meters

Area of the rectangular park = length × width

= 100 × 120

= 1200 square meters

Therefore, Scale factor from actual length to the length in drawing = 1 : 20

Area of the rectangular park = 1200 square feet

7 0

3 years ago

Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly's kites are shown below on the coor

Alex787 [66]

The correct answer is:

C. They are similar because the corresponding sides of kites KELY and BRAD all have the relationship 2:1.

Using the distance formula,

$d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

the lengths of the sides of BRAD are:

$\text{BR}=\sqrt{(7-6)^2+(3-4)^2}=\sqrt{1^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}\\\\\text{RA}=\sqrt{(6-3)^2+(4-3)^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{AD}=\sqrt{(3-6)^2+(3-2)^2}=\sqrt{(-3)^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{DB}=\sqrt{(6-7)^2+(2-3)^2}=\sqrt{(-1)^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}$

The lengths of the sides of KELY are:

$\text{KE}=\sqrt{(2-0)^2+(11-9)^2}=\sqrt{2^2+2^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\\\\\text{EL}=\sqrt{(0-2)^2+(9-3)^2}=\sqrt{(-2)^2+6^2}=\sqrt{40}=2\sqrt{10}\\\\\text{LY}=\sqrt{(2-4)^2+(3-9)^2}=\sqrt{(-2)^2+(-6)^2}=\sqrt{40}=2\sqrt{10}\\\\\text{YK}=\sqrt{(4-2)^2+(9-11)^2}=\sqrt{2^2+(-2)^2}=\sqrt{8}=2\sqrt{2}$