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3 years ago

The atomic mass of an element is the sum of neutrons and A) atoms. B) electrons. C) isotopes. D) protons.

Chemistry

2 answers:

Basile [38]3 years ago

4 0

I Would Say The Answer Is D.

Elis [28]3 years ago

3 0

Answer: D) protons.

The other option that would make the most sense would be electrons, however the mass of an electron is so small that is basically negligible, so it's not included in the atomic mass.

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separating a solid from a liquid by evaporating is called _____ a) filtration b) condensation c) solution d) distillation

tatiyna

D) Distillation is the process used to separate a solid from a liquid through <span>evaporating the liquid..</span>

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3 years ago

Read 2 more answers

I NEED HELP PLEASE, THANKS! :)

marin [14]

Answer:

$\large \boxed{1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2 }}$

Explanation:

1. Calculate the moles of copper(II) hydroxide

$\text{Moles of Cu(OH)}_{2} = \text{23.45 g Cu(OH)}_{2} \times \dfrac{\text{1 mol Cu(OH)}_{2}}{\text{97.562 g Cu(OH)}_{2}} = \\\\\text{0.240 36 mol Cu(OH)}_{2}$

2. Calculate the molecules of copper(II) hydroxide

$\text{No. of molecules} = \text{0.240 36 mol Cu(OH)}_{2} \times \dfrac{6.022 \times 10^{23}\text{ molecules Cu(OH)}_{2}}{\text{1 mol Cu(OH)}_{2}}\\\\= 1.447 \times 10^{23}\text{ molecules Cu(OH)}_{2}\\\text{The sample contains $\large \boxed{\mathbf{1.447 \times 10^{23}}\textbf{ molecules Cu(OH)}_{\mathbf{2}}}$}$

6 0

3 years ago

How do you balance this chemical equation?

garik1379 [7]

Answer:

i will help hold up

Explanation:

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3 years ago

What volume of a 5.00M solution of hydrochloric acid contains 8.00mol of HCl?

rjkz [21]

Answer:

520ML and apparently I need to put more in this answer

Explanation:

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3 years ago

How much energy will it take to raise the temperature of 75.0 g of water from 20.0°C to 55.0°C?

Hatshy [7]

Answer:

We can use heat = mcΔT to determine the amount of heat, but first we need to determine ΔT. Because the final temperature of the water is 55°C and the initial temperature is 20.0°C, ΔT is as follows:

ΔT = Tfinal − Tinitial = 55.0°C − 20.0°C = 35.0°C

given the specific heat of water as 1 cal/g·°C. Substitute the known values into heat = mcΔT and solve for amount of heat:

= heat=(75.0 g)(1 cal/ g· °C )(35.0°C) =

= 75x1x35=2625 cal

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3 years ago