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3 years ago

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Last week, a coral reef grew 19.5 mm taller. How much did it grow in meters?

2 answers:

lianna [129]3 years ago

8 0

0.0195

ANswer

Answer

Answer

makvit [3.9K]3 years ago

4 0

Answer:

Last week, a coral reef grew 19.5 mm taller. How much did it grow in meters?

Step-by-step explanation:

So it's hard to explain but simply Milli witch is the symbol "m" is a unit prefix in the metric system denoting a factor of one thousandth (10 −3). So 19.6mm is 19.6*10^-3m. in other words 19.6 times 10^-3m

hope this helps sorry it's so complicated :/

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(4x + 4) (5x + 2) =

kirill115 [55]

Answer:

Step-by-step explanation:

20x^2+28x+8

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2 years ago

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Find the distance between a point (– 2, 3 – 4) and its image on the plane x+y+z=3 measured across a line (x + 2)/3 = (2y + 3)/4

dimaraw [331]

Answer:

Distance of the point from its image = 8.56 units

Step-by-step explanation:

Given,

Co-ordinates of point is (-2, 3,-4)

Let's say

$x_1\ =\ -2$

$y_1\ =\ 3$

$z_1\ =\ -4$

Distance is measure across the line

$\dfrac{x+2}{3}\ =\ \dfrac{2y+3}{4}\ =\ \dfrac{3z+4}{5}$

So, we can write

$\dfrac{x-x_1+2}{3}\ =\ \dfrac{2(y-y_1)+3}{4}\ =\ \dfrac{3(z-z_1)+4}{5}\ =\ k$

$=>\ \dfrac{x-(-2)+2}{3}\ =\ \dfrac{2(y-3)+3}{4}\ =\ \dfrac{3(z-(-4))+4}{5}\ =\ k$

$=>\ \dfrac{x+4}{3}\ =\ \dfrac{2y-3}{4}\ =\ \dfrac{3z+16}{5}\ =\ k$

$=>\ x\ =\ 3k-4,\ y\ =\ \dfrac{4k+3}{2},\ z\ =\ \dfrac{5k-16}{3}$

Since, the equation of plane is given by

x+y+z=3

The point which intersect the point will satisfy the equation of plane.

So, we can write

$3k-4+\dfrac{4k+3}{2}+\dfrac{5k-16}{3}\ =\ 3$

$=>6(3k-4)+3(4k+3)+2(5k-16)\ =\ 18$

$=>18k-24+12k+9+10k-32\ =\ 18$

$=>\ k\ =\dfrac{13}{8}$

So,

$x\ =\ 3k-4$

$=\ 3\times \dfrac{13}{8}-4$

$=\ \dfrac{7}{4}$

$y\ =\ \dfrac{4k+3}{2}$

$=\ \dfrac{4\times \dfrac{13}{8}+3}{2}$

$=\ \dfrac{19}{4}$

$z\ =\ \dfrac{5k-16}{3}$

$=\ \dfrac{5\times \dfrac{13}{8}-16}{3}$

$=\ \dfrac{-21}{8}$

Now, the distance of point from the plane is given by,

$d\ =\ \sqrt{(x-x_1)^2+(y-y_1)^2+(z-z_1)^2}$

$=\ \sqrt{(-2-\dfrac{7}{4})^2+(3-\dfrac{19}{4})^2+(-4+\dfrac{21}{8})^2}$

$=\ \sqrt{(\dfrac{-15}{4})^2+(\dfrac{-7}{4})^2+(\dfrac{9}{8})^2}$

$=\ \sqrt{\dfrac{225}{16}+\dfrac{49}{16}+\dfrac{81}{64}}$

$=\ \sqrt{\dfrac{1177}{64}}$

$=\ 4.28$

So, the distance of the point from its image can be given by,

D = 2d = 2 x 4.28

= 8.56 unit

So, the distance of a point from it's image is 8.56 units.

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3 years ago

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Dafna1 [17]

Answer:

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Step-by-step explanation:

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2 years ago

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amid [387]

Answer:

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Step-by-step explanation:

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2 years ago

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Suppose that two fair dice are rolled. find the probability that the number on the first die is a 1 or the number on the second

Bogdan [553]

Answer:

1/36

Step-by-step explanation:

Assuming the dice has 6 sides in total, we can set up a probability for each scenario.

The chances of the dice landing on 1 will be 1/6, since there are 6 total faces. Same goes for the second die and landing on 4.

Now that we have our 2 probabilities, we multiply them to get the final probability. 1/6 x 1/6 = 1/36.

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2 years ago