The answer is .35 not 3.5
1260-360-360-360=180
Therefore,180
It depends on what level of classes you take, but algebra classes in college do tend to be harder than algebra classes in high school or middle school.
<span>Given:
f(0) = 2</span>
So first of all, we let x = 2012, y = 0:
<span>
Then, F(2012) = 2012 + f(0)
Since f(0) = 2, then f(2012) = 2012 + 2 = 2014.
To add, </span>the process that relates an input to an output is called a
function.
<span>There are always three main parts of a
function, namely:
</span>Input
The Relationship
The Output
The classic way of writing a function is
"f(x) = ... ".
What goes into the function
is put inside parentheses () after the name of the function: So, f(x) shows us the
function is called "f", and "x" goes in.
What a function does with the input can be usually seen as:
<span>f(x) = x2</span><span> reveals to us that function "f" takes "x<span>" and squares
it.</span></span>
To justify the yearly membership, you want to pay at least the same amount as a no-membership purchase, otherwise you would be losing money by purchasing a yearly membership. So set the no-membership cost equal to the yearly membership cost and solve.
no-membership costs $2 per day for swimming and $5 per day for aerobic, in other words, $7 per day. So if we let d = number of days, our cost can be calculated by "7d"
a yearly membership costs $200 plus $3 per day, or in other words, "200 + 3d"
Set them equal to each other and solve:
7d = 200 + 3d
4d = 200
d = 50
So you would need to attend the classes for at least 50 days to justify a yearly membership. I hope that helps!
