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MAVERICK [17]
2 years ago
5

Hank put $10,000 in an account for 10 years. The account earned 2.5% interest. How much interest had been earned by the end of t

he 10 years?
Mathematics
1 answer:
NeX [460]2 years ago
4 0

Answer:

A = P ( 1+ i )^n

A = 10,000(1+0.025)^10

= 10,000(1.025)^10

= $12,800.84

Step-by-step explanation:

A = future amount

i = interest rate

n = number of years

P = Present value

i.e i = 2.5% , P = $10,000 and n = 10 years

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Answer:

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Has exactly one pair of parallel sides.

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The exponential functions change is represented by decay and the percentage rate of decrease is 1.00619%.

Step-by-step explanation:

Step 1:

To determine if the function represents growth or decay, we substitute values to x.

If the values increase with an increase of x, it represents growth.

If the values decrease with an increase of x, it represents decay.

Step 2:

If x= 10, y = 1,300 (\frac{1}{2})^{\frac{10}{69} }  =  1,300 (0.9044) = 1,175.72.

If x=11,y = 1,300 (\frac{1}{2})^{\frac{11}{69} }  =  1,300 (0.8953) = 1,163.89.

So as x increases the value of y decreases, so it represents decay.

Step 3:

The percentage rate of change is determined by dividing the difference of two consecutive values by the first value.

The percentage rate of change = \frac{y(x=11) - y(x=10)}{y(x=10)}.

Substituting the values, we get

The percentage rate of change =\frac{1,175.72-1,163.89}{1,175.72}(100) = 1.00619\%.

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Prove algebraically that r = 10/2+2sinTheta is a parabola
Xelga [282]

Answer:

y =  -  \frac{ 1 }{10} {x}^{2}   +  \frac{5}{2}

Step-by-step explanation:

We want to prove algebraically that:

r =  \frac{10}{2 + 2 \sin \theta}

is a parabola.

We use the relations

{r}^{2}  =  {x}^{2}  +  {y}^{2}

and

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Before we substitute, let us rewrite the equation to get:

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We now substitute to get:

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