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Allisa [31]
3 years ago
13

3/5 ÷ 1 1/4 = (20 points)

Mathematics
1 answer:
Anna11 [10]3 years ago
7 0

3/5 ÷ 1 1/4 = 0.48

0.48 will be your anwer


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A petrol kiosk p is 12 km due north of another petrol kiosk q. The bearing of a police station r from p is 135 degree and that f
tiny-mole [99]

Answer:

Distance between P and R is 40.15 km.

Step-by-step explanation:

From the picture attached,

Petrol kiosk P is 12 km due North of another petrol kiosk Q.

Bearing of a police station R is 135° from P and 120° from Q.

m∠QPR = 180° - 135° = 45°

m∠PQR = 120°

m∠PRQ = 180° - (m∠QPR +m∠PQR)

             = 180° - (45° + 120°)

             = 180° - 165°

             = 15°

Now we apply sine rule in ΔPQR to measure the distance between P and R.

\frac{\text{sin}(\angle QPR)}{\text{QR}}= \frac{\text{sin}(\angle PQR)}{\text{PR}}=\frac{\text{sin}\angle PRQ}{\text{PQ}}

\frac{\text{sin}(45)}{\text{QR}}= \frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

\frac{\text{sin}(120)}{\text{PR}}=\frac{\text{sin}(15)}{\text{12}}

PR = \frac{12\text{sin}(120)}{\text{sin}(15)}

PR = 40.15 km

Therefore, distance between P and R is 40.15 km.

8 0
3 years ago
I GIVE BRAINLIEST! LOOK AT THE IMAGE BELOW.
MissTica
Answer: 8

Area of a triangle=(1/2)bh
16=(1/2)4x
16=2x
x=8
3 0
3 years ago
Find m∠XYW and m∠WYZ m
makvit [3.9K]

Answer:

<XYZ = 117°

<XYW+ WYZ = 117°

(6x+44)+(-10x+65)= 117°

6x+44-10x+65= 117°

-4x+ 109= 117°

-4x= 117-109

-4x= 8

x= 8/-4

x= -2

<XYW= 6x+44= 6×-2+44= -12+44= 32°

<WYZ= -10x+65 = -10×-2+ 65= 20+65= 85°

Step-by-step explanation:

7 0
3 years ago
In the figure below, points J, K, and L are the midpoints of the sides of AXYZ.
Dima020 [189]

Answer:

<em>28 ; 76 ; 38</em>

Step-by-step explanation:

<em>KL</em> = \frac{XY}{2} = \frac{56}{2} = <em>28</em> units

<em>YZ</em> = 2 × JK = 38 × 2 = <em>76</em> units

<em>LZ</em> = 76/2 = <em>38</em> units

8 0
3 years ago
Read 2 more answers
Which of the following tables represents a function? x 2 2 3 3 y 5 −5 6 −6 x 4 −4 4 −4 y 1 2 3 4 x 6 6 7 7 y 2 3 4 5 x 2 −2 4 −4
Crank

Answer: Fourth option.

Step-by-step explanation:

By definition, a relationship is a function if and only if each input value (or each x-value) has only one output value (or y-value).

Given the first table:

x|2\ \ 2\ \ 3\ \ 3\\y|5-5\ 6-6

You can notice that the input values 2 and 3 do not have only one output value. Therefore, this table does not represent a function.

The second table is:

x|4-4\ 4\ -4\\y|1\.\ \ 2\ \.\ \ 3\ \ 4

 You can notice that the input values 4 and -4 do not have only one output value. Therefore, this table does not represent a function.

The third table is:

x| 6\ 6\ 7\ 7\ \\y|2\ 3\ 4\ 5

 You can notice that the input values 6 and 7 do not have only one output value. Therefore, this table does not represent a function.

The fourth table is:

x| 2\ -2\ 4\ -4\ \\y|8\ \.\ \ 8\ \ 12\ \ 12

 You can notice that each input value has only one output value. Therefore, this table represents a function.

4 0
3 years ago
Read 2 more answers
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