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MrRissso [65]
4 years ago
6

If two electrons in the same atom have the same value of "l", they are If two electrons in the same atom have the same value of

"l", they are in the same orbital. in the same level, but different sublevel. in the same sublevel, but not necessarily in the same level. in different levels and in different shaped orbitals. none of the above.
Chemistry
1 answer:
Semenov [28]4 years ago
5 0

Answer: Option (e) is the correct answer.

Explanation:

As we know that value of l depends on the value of n, that is, principle quantum number.

Since, relation between l and n is as follows.

                 l = (n - 1)

For example, suppose two electrons in the same atom have value of n = 2. So, the value of l will be as follows.

                    l = (2 - 1)

                      = 1

That means there will be s and p shells present in the atom. As the values of both l and n  are fixed. Therefore, electrons will be present in same level and same sub-shell.

Thus, we can conclude that none of the given statements are correct.

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Answer:

Explanation:

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Frank has a sample of steel that weighs 80 grams. If the density of his sample of steel is 8 g/cm3, what is the sample’s volume?
IRINA_888 [86]
Density (p) is defined as the mass (m) per unit volume (v) or:

p = m/v 

Using this relationship, the volume is:

v = m/p

Using the given values of mass of 80 grams and density of 8 g/cm3, the sample volume is:

v = 80 grams/8 grams/cm3
v = 10 cm3

The final answer is 10 cm3.
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4 years ago
Using a molar heat of combustion of hexane (C6H14) –4163 kJ/mol, the mass of hexane required to increase the temperature of 1.76
pshichka [43]

Answer:

7.46 g.

Explanation:

  • Firstly, we need to calculate the amount of heat needed to warm 5.64 kg of water from 21.0°C to 70.0°C using the relation:

<em>Q = m.c.ΔT,</em>

where, Q is the amount of heat absorbed by water (Q = ??? J).

m is the mass of water <u><em>(m: we will determine).</em></u>

c is the specific heat capacity of water (c = 4.186 J/g.°C).

ΔT is the temperature difference (final T - initial T) (ΔT =  70.0 °C - 21.0 °C = 49.0 °C).

  • To determine the mass of 1.76 L of water we can use the relation:

mass = density x volume.

density of water = 1000 g/L & V = 1.76 L.

∴ mass = density x volume = (1000 g/L)(1.76 L) = 1760.0 g.

∵ Q = m.c.ΔT

<em>∴ Q = m.c.ΔT </em>= (1760.0 g)(4.186 J/g.°C)(49.0 °C) = 360483.2 J ≅ 360.4832 kJ.

  • As mentioned in the problem the molar heat of combustion of hexane is - 4163.0 kJ/mol.

<em>Using cross multiplication we can get the no. of moles of hexane that are needed to be burned to release 360.4832 kJ:</em>

Combustion of 1.0 mole of methane releases → - 4163.0 kJ.

Combustion of ??? mole of methane releases → - 360.4832 kJ.

∴ The no. of moles of hexane that are needed to be burned to release 360.4832 kJ = (- 360.4832 kJ)(1.0 mol)/(- 4163.0 kJ) = 0.0866 mol.

  • Now, we can get the mass of hexane that must be burned to warm 1.76 L of water from 21.0°C to 70.0°C:

<em>∴ mass = (no. of moles needed)(molar mass of hexane)</em> = (0.0866 mol)(86.18  g/mol) = <em>7.46 g.</em>

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A hydrocarbon with general formaul cxhy is burned completely in air yielding 0.18 g of water and 0.44 g of carbon dioxide. Which
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Answer:

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Explanation:

When a hydrocarbon is burnt in air or oxygen, there are two products only, these are water and carbon iv oxide.

Fuel + Oxygen—-> Water + Carbon iv oxide

We can get the formula through calculations as follows.

From the mass of carbon iv oxide produced, we can get the number of moles of carbon produced. We first divide the mass by the molar mass of carbon iv oxide. The molar mass of carbon iv oxide is 44g/mol

The number of moles of carbon iv oxide is 0.44/44 = 0.01

Since there is only one carbon atom in CO2, the number of moles of carbon is same as above I.e 0.01 moles

From the number of moles of water, we can get the number of moles of hydrogen. To get the number of moles of water, we need to divide the mass of water by its molar mass. Its molar mass is 18g/mol. The number of moles here is thus 0.18/18 = 0.01moles

But there are 2 atoms of hydrogen in 1 mole of water and thus, the number of moles of hydrogen is 2 * 0.01= 0.02moles

The empirical formula can be obtained by dividing the number of moles of each by the smallest which is that of 0.01

H = 0.02/0.01 = 2

C = 0.01/0.01 = 1

From the calculations, x = 1 and y = 2

The empirical formula is thus CH2

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