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Andrej [43]
3 years ago
5

Frank has a sample of steel that weighs 80 grams. If the density of his sample of steel is 8 g/cm3, what is the sample’s volume?

Chemistry
1 answer:
IRINA_888 [86]3 years ago
7 0
Density (p) is defined as the mass (m) per unit volume (v) or:

p = m/v 

Using this relationship, the volume is:

v = m/p

Using the given values of mass of 80 grams and density of 8 g/cm3, the sample volume is:

v = 80 grams/8 grams/cm3
v = 10 cm3

The final answer is 10 cm3.
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Mixture. Distilled Water may be a pure substance, however, there are many minerals and such that are in tap water, making it a mixture.

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You have 350 mL of 3.4 M hydrochloric acid (HCl). How many grams of HCl gas are dissolved? Bonus: what is the volume of the HCl
Crank

Answer:

1. 43.44g of HCl

2. 26.67 L of HCl

Explanation:

1) Molarity of a solution = number of moles (n) ÷ Volume (V)

According to the provided information in this question,

V = 350 mL = 350/1000 = 0.350L

Molarity = 3.4 M

Using Molarity = n/V

3.4 = n/0.350

n = 3.4 × 0.350

n = 1.19mol

Using the formula below to calculate the mass of HCl;

mole = mass/molar mass

Molar mass of HCl = 1 + 35.5 = 36.5g/mol

mole = mass/MM

mass = 1.19 mol × 36.5g/mol

mass = 43.44g of HCl

2) At STP, HCl has a pressure of 1atm, a temperature of 273K

V = ?

n = 1.19 mol

R = 0.0821 Latm/molK

Using PV = nRT

V = nRT/P

V = 1.19 × 0.0821 × 273/1

Volume = 26.67L

5 0
3 years ago
2. What is one effect of convection currents in the mantle?
Rom4ik [11]

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D no. is the answer of your question

8 0
3 years ago
To which group of alcohols does 3,4-dimethyl-2-pentanol belong?
dsp73

Answer:

The answer is A

Explanation:

8 0
2 years ago
300 mL of 0.200 M Pb(NO3)2 is added to 200 mL of 0.0500 M NaCl(aq) at 25°C. Will a precipitate of PbCl2 form at 25 °C? Tip: You
Bas_tet [7]

Explanation:

It is given that volume of Pb(NO_{3})_{2} is 300 mL and molarity is 0.200 M.

Volume of NaCl is 200 mL and molarity is 0.050 M.

The chemical reaction will be as follows.

            PbCl_{2}(s) \rightleftharpoons Pb^{2+}(aq) + 2Cl^{-}(aq)

K_{sp} for PbCl_{2} is given as 1.7 \times 10^{-5}.

As, molarity is number of moles present in liter of solution.

Hence, moles of Pb^{2+}(aq) will be calculated as follows.

         moles of Pb^{2+}(aq) = 0.300 L \times 0.200 M

                                                = 0.06 mol

                      [Pb^{2+}] = \frac{0.06 mol}{0.5 L}

                                            = 0.120 M

Mole of Cl^{-}(aq) = 0.2 L \times 0.05 M  

                                  = 0.010 M

Now,   Q = [Pb^{2+}][Cl^{-}]^{2}

                  = 0.120 \times (0.010)^{2}

                  = 1.2 \times 10^{-5}    

As, Q < K_{sp} hence, there will be no formation of PbCl_{2} precipitate.

3 0
3 years ago
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