Option C:
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Solution:
Area of the square paper = 
sq. cm
Area of the square corner removed = 16 sq. cm
Let us find the area of the remaining paper.
Area of the remaining paper = Area of the square paper – Area of the corner
Area of the remaining = 
= 
Using algebraic formula: 
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Hence (3x – 4)(3x + 4) represents area of the remaining paper in square centimeters.
Answer:
B y= 4.50x + 5.00
Step-by-step explanation:
4.50 is the “mx” in y=mx+b also known as the Slope that moves.
the 5 is the ”b” which is the y-intercept. It is a constant and does not change.
Answer:
Hello, the answer would be A. ∠2
Step-by-step explanation:
Hope this helps!
Brainliest please.
Answer:
n = π/6, π/4, 3π/4, 5π/6
Step-by-step explanation:
sin(3n) − sin n = cos(2n)
Use double and triple angle formulas:
(3 sin n − 4 sin³ n) − sin n = 1 − 2 sin² n
2 sin n − 4 sin³ n = 1 − 2 sin² n
4 sin³ n − 2 sin² n − 2 sin n + 1 = 0
Factor by grouping:
2 sin² n (2 sin n − 1) − (2 sin n − 1) = 0
(2 sin² n − 1) (2 sin n − 1) = 0
Solve:
2 sin² n − 1 = 0
2 sin² n = 1
sin² n = 1/2
sin n = √2/2
n = π/4, 3π/4
2 sin n − 1 = 0
2 sin n = 1
sin n = 1/2
n = π/6, 5π/6
Answer:
x=4
Step-by-step explanation:
tangent lines from the same point to a circle are congruent in length, so we can say that
5x+8 = 8x-4
5x -5x +8 = 8x - 5x -4
8 = 3x - 4
8+4 = 3x -4 + 4
3x = 12
3x/3 = 12/3
x=4
