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Scorpion4ik [409]
3 years ago
14

What is the relative energy expense of galloping rather than trotting at 3.5 m/s?

Physics
1 answer:
labwork [276]3 years ago
7 0

Answer: Trotting uses only 75 percent of the energy as galloping

Explanation: Trotting is only 300 J/m, whereas galloping is roughly 400 J/m

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If you double the distance between you and the center of Earth, what happens to the strength of the gravitational field you expe
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The strength of gravity decreases.

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A mass tied to the end of a 1.0 m-long string is swinging back and forth From its lowest point, the mass moves 4 cm to the right
ehidna [41]

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3 years ago
A charged capacitor is connected to an ideal inductor to form an LC circuit with a frequency of oscillation f = 1.6 Hz. At time
IrinaK [193]

Answer:

8.0\mu C

Explanation:

We are given that

f=1.6 Hz

q=3.0\mu C=3.0\times 10^{-6} C

1\mu C=10^{-6} C

Current,I=75\mu A=75\times 10^{-6} A

1\mu A=10^{-6} A

We have to find the maximum charge of the capacitor.

Charge on the capacitor,q=q_0cos\omega t

\omega=2\pi f=2\pi\times 1.6=3.2\pi rad/s

3\times 10^{-6}=q_0cos3.2\pi t....(1)

I=\frac{dq}{dt}=-q_0\omega sin\omega t

75\times 10^{-6}=-q_0(3.2\pi)sin3.2\pi t....(2)

Equation (2) divided by equation (1)

-3.2\pi tan3.2\pi t=\frac{75\times 10^{-6}}{3\times 10^{-6}}=25

tan3.2\pi t=-\frac{25}{3.2\pi}=-2.488

3.2\pi t=tan^{-1}(-2.488)=-1.188rad

q_0=\frac{q}{cos\omega t}=\frac{3\times 10^{-6}}{cos(-1.188)}=8.0\times 10^{-6}=8\mu C

Hence, the maximum charge of the capacitor=8.0\mu C

4 0
4 years ago
How did private industries benefit from military expenditures?
Dafna11 [192]

Answer:

option A: the government paid private industries for goods and services.

Explanation:

8 0
2 years ago
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