1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mel-nik [20]
4 years ago
15

As you bring a prism close to the angle of total internal reflection, what happens to the angle of the refracted beam outside th

e prism? What happens to its intensity? What happens to the intensity of the beam inside the prism?
Physics
1 answer:
EleoNora [17]4 years ago
5 0

Answer:

Explanation:

Total Internal Reflection (TIR) occurs when the angle of incident exceeds the value of critical angle and as a result of which the light gets internally reflected and does not refract the light enters at one point and exits at the other like that of an optical fiber.

Critical angle is defined as that incident angle for which the refracted angle is a right angle.

Now, in case a prism is brought close to the angle of TIR, the refracted beam angle increases up to the point where it reaches 90^{\circ}.

As it exceeds 90^{\circ}, the beam will be internally reflected without any refraction. So, in reaching the point of TIR, the intensity of the refracted beam decreases and is completely diminished to 0 at critical angle.

The beam intensity inside the prism increases and is maximum at the point of TIR, i.e., at critical angle.

Once TIR is initiated, i.e., the angle exceeds the critical angle, internal reflection occurs with no refracted rays.

You might be interested in
Forest protect the soil from erosion ? True or False
Ivenika [448]

Answer:

<h2><em>True</em></h2>

Forests helps in binding the soil together. Thus, prevent soil from erosion.

4 0
2 years ago
Read 2 more answers
You have decided that you are ready to start a fitness program. Why is it important to set short-term and long-term goals?
suter [353]

Answer:

Setting short-term and long-term goals is very important to stay on track and motivated to improve fitness levels. You can keep track of your progress by weighing yourself every day to track weight loss, and by steadily increasing the difficulty of the exercises to track your strength improvement. It is very important to reflect on progress, so you can evaluate what you need to do in the future to remain on track, as well as seeing how much you've improved.

5 0
3 years ago
Which statement about the speed of light is true?
kolezko [41]
' B ' is the only true one.
5 0
4 years ago
A crate is dragged up a ramp at constant speed. The work done on the system can be accounted for by:
Alex

Answer:

The work done on the system can be accounted for by;

Both E_g and E_{int}

Explanation:

The speed of the crate = Constant

Therefore, the acceleration of the crate = 0 m/s²

The net force applied to the crate, F_{NET} = 0

Therefore, the force of with which the crate is pulled = The force resisting the upward motion of the crate

However, we have;

The force resisting the upward motion of the crate = The weight of the crate + The frictional resistance of the ramp due to the surface contact between the ramp and the crate

The work done on the system = The energy to balance the resisting force = The weight of the crate × The height the crate is raised + The heat generated as internal energy to the system

The weight of the crate × The height the crate is raised = Gravitational Potential Energy = E_g

The heat generated as internal energy to the system = E_{int}

Therefore;

The work done on the system = E_g + E_{int}.

6 0
3 years ago
A horizontal force of 150 N is used to push a 40.0-kg packing crate a distance of 6.00 m on a rough horizontal surface. If the c
icang [17]

Answer:

a. 900 J

b. 0.383

Explanation:

According to the question, the given data is as follows

Horizontal force = 150 N

Packing crate = 40.0 kg

Distance = 6.00 m

Based on the above information

a. The work done by the 150-N force is

W = F x = \mu N x = \mu\ m\ g\ x

W = 150 \times 6

= 900 J

b. Now the coefficient of kinetic friction between the crate and surface is

\mu = \frac {F}{m\timesg}

= \frac{150}{40\times 9.8}

= .383

We simply applied the above formulas so that each one part could calculate

3 0
4 years ago
Other questions:
  • A student has made the statement that the electric flux through one half of a Gaussian surface is always equal and opposite to t
    13·1 answer
  • Consider that 168.0 J of work is done on a system and 305.6 J of heat is extracted from the system. In the sense of the first la
    13·1 answer
  • Plane is flying east at 33m/s an airplane is also being carried due north at 12 m/s by the wind what is the planes resultant vel
    9·1 answer
  • A measure of how far an object has moved from a starting point
    6·1 answer
  • A cannon is mounted on a tower above a wide, level field. The barrel of the cannon is 20 m above the ground below. A cannonball
    7·1 answer
  • The path followed by a projectile is called its _____.
    11·2 answers
  • An object moving with a speed v0 collides head-on with a second object initially at rest. A student assumes the collision is ela
    13·1 answer
  • 2. Andy is accelerating at 2 m/s?. If he started from a stand still and he has been
    9·1 answer
  • Which of the following statements is true
    7·2 answers
  • Q4. Convert these into proper vector notation:
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!