You wish to lift a 12,000 lb stone by a vertical distance of 15 ft. Unfortunately, you can only generate a maximum pushing force

Question

2 years ago

5

of 2,000 lb. What is the amount of work you must input in order to move the stone

1 answer:

DochEvi [55] · Answer 1 · 2022-06-19T10:22:10+03:00

6 0

Answer:

5,760,000 lb-ft²/s²

Explanation:

Work done, W = mgy where m = mass of stone = 12,000 lb, g = 32 ft/s² and y = vertical distance = 15 ft.

So, W = mgy = 12,000 lb × 32 ft/s² × 15 ft. = 5,760,000 lb-ft²/s²