Question

A number cube is tossed and a spinner is spun. What is the probability of getting a 3 or 4 on the number cube and not getting 8 on the spinner?

Answer 1

Answer:

7/24

Step-by-step explanation:

Given in the question,

a number cube is tossed and a spinner is spun.

Cube have 6 in numbers

1 2 3 4 5 6

probability of having 3 or 4 = 2/6

                                             = 1/3

                           

Spinners are commonly made with 6, 8, 10 and 12 flat surfaces.

If a spinner has 8 flats then you have a 7/8 chance of not getting an 8.

Probability of getting a 3 or 4 on the number cube and not getting 8

"and" mean multiplication

7/8 x 1/3

7/24

Answer 2

Answer:

P = 0.2917

Step-by-step explanation:

There are 6 possible results for the cube numbered {1, 2, 3, 4, 5, 6}

There are 8 possible results for the spinner.

Then the amount of results that can be obtained from the combination of these experiments is:

$S = 6 * 8 = 48$  possible outcomes.

Then, we seek to obtain a 3 or a 4 and in the spinner any number other than 8.

exist

$S = 2 * 7 = 14$  possible ways to obtain this result.

Then the probability sought is:

$P = \frac{14}{48}\\\\P = 0.2917$