Let A( t , f( t ) ) be the point(s) at which the graph of the function has a horizontal tangent => f ' ( t ) = 0.
But, f ' ( x ) = [ ( x^2 ) ' * ( x - 1 ) - ( x^2 ) * ( x - 1 )' ] / ( x - 1 )^2 =>
f ' ( x ) = [ 2x( x - 1 ) - ( x^2 ) * 1 ] / ( x - 1 )^2 => f ' ( x ) = ( x^2 - 2x ) / ( x - 1 )^2;
f ' ( t ) = 0 <=> t^2 - 2t = 0 <=> t * ( t - 2 ) = 0 <=> t = 0 or t = 2 => f ( 0 ) = 0; f ( 2 ) = 4 => A 1 ( 0 , 0 ) and A 2 ( 2 , 4 ).
Answer:
1. $1.40 2. $8.40
Step-by-step explanation:
1. 7 divided by 5 is 1.4
2. 1.40 plus $7 equals $8.40
Answer:
207.24 inches
Hope this helps
Step-by-step explanation:
first you need to find the circumference...
2pi R (r=radius=11)
2 x 3.14 x 11 = 69.08 (i'm using 3.14 as pi so yea...)
3 rotations...
69.08 x 3= 207.24 inches
I think it would be 72+4x=400
400-72= 328
328/4= 82
So the answer would be 82=x
The answer is minus 666 that’s the answer byee
