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3 years ago

A cube has a volume of 343 cm3. What is the length of each side of the cube?

1 answer:

3 0

Volume of a cube=side³

Data:;
volume=343 cm³
Therefore:

343 cm³=side³
side=∛343 cm³=7 cm.

Answer: the lenght of each side of the cube is 7 cm.

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35 inches in diameter what is the radius

Masja [62]

Radius = diameter/2

35/2 = 17.5

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3 years ago

7+4u=70-3u What is U

ruslelena [56]

$7+4u=70-3u \\ 7+4u+3u=70-3u+3u \\ 7+7u=70 \\ 7-7+7u=70-7 \\ 7u=63 \\ 7u/7=63/7 \\ u=9$
u=9 is your answer.
Hope this helps!

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3 years ago

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1. What is the area of the triangle below? 10 in. 7 in.

Alex787 [66]

The area of a triangle is

$\cfrac{base*height}{2}$

If we plug in the given values, we get:

$\frac{10*7}{2}$

Multiply in the numerator:

$\frac{70}{2}$

Divide:

$35$

Therefore, the area of the triangle is 35 inches squared.

6 0

3 years ago

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The quadratic equation 2x^2 + bx + 18 = 0 has a double root. Find all possible values of b.

Doss [256]

When a quadratic equation ax^2+bx+c has a double root, the discriminant,
D=b^2-4ac=0
Here
a=2,
b=b,
c=18
and
D=b^2-4ac=b^2-4*2*18=0
solve for b
b^2-144=0
=> b= &pm; sqrt(144)= &pm; 12

So in order that the given equation has double roots, the possible values of b are &pm; 12.

4 0

3 years ago

The vertices of a triangle ABC are A(7, 5), B(4, 2), and C(9, 2). What is measure of angle ABC? 30° 45° 56.31° 78.69°

GenaCL600 [577]

The measure of angle ABC is 45°

Explanation

Vertices of the triangle are: A(7, 5), B(4, 2), and C(9, 2)

According to the diagram below....

Length of the side BC (a) $=\sqrt{(4-9)^2+(2-2)^2}= \sqrt{25}= 5$

Length of the side AC (b) $= \sqrt{(7-9)^2 +(5-2)^2}= \sqrt{4+9}=\sqrt{13}$

Length of the side AB (c) $= \sqrt{(7-4)^2 +(5-2)^2} =\sqrt{9+9}=\sqrt{18}$

We need to find ∠ABC or ∠B . So using Cosine rule, we will get...

$cosB= \frac{a^2+c^2-b^2}{2ac} \\ \\ cos B= \frac{(5)^2+(\sqrt{18})^2-(\sqrt{13})^2}{2*5*\sqrt{18} }\\ \\ cosB= \frac{25+18-13}{10\sqrt{18}} =\frac{30}{10\sqrt{18}}=\frac{3}{\sqrt{18}}\\ \\ cosB=\frac{3}{3\sqrt{2}} =\frac{1}{\sqrt{2}}\\ \\ B= cos^-^1(\frac{1}{\sqrt{2}})= 45 degree$

So, the measure of angle ABC is 45°

7 0

4 years ago

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