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SVETLANKA909090 [29]
3 years ago
11

Tiana's math test score are 85 and 91 . she has one more test left. in order to earn and a, her average test score must be at le

ast 94. let x represent tiana's score on her next test. which inequalities could represent the possible test scores she can earn on the next test in order to earn an a? select all that apply
a. 94<85 91/2<100
b. 94<176 x/2<100
c. 94<85 91 x/3<100
d. 94<176/3<100
e. 94<=176 x/3<100
Mathematics
1 answer:
Harrizon [31]3 years ago
3 0
"at least " means her score has to be more or equal 94
94≤(85+91+x)/3
it looks like correct answer is e.

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A mountain climber starts a climb at an elevation of 453 feet above sea level. At his first rest stop he has climbed 162 feet, a
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They started at 453, then climbed 162, so now they are at:

453 + 162 = 615 feet.

They then cllmb another 207 feet to get to:

615 + 207 = 822 feet.

They then descend ( climb down) 285 feet.

822 - 285 = 537 feet.

Now they need to get back tot he original 453,

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537 - 453 = 84 more feet.

The answer is C.

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2. Gerald was given the following problem to solve for the length of the "?". He has made a mistake in his work.
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Answer:

x = 18.7

Step-by-step explanation:

Gerald's answer is almost correct.  

He just needs to switch the 14 and the x.

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5 0
3 years ago
Given: ∆ABC, m∠C = 90° CB = 8, m∠B = 38º Find the area of a circumscribed circle. Find the area of the inscribed circle.
vitfil [10]

Answer:

Circumscribed circle: Around 80.95

Inscribed circle: Around 3.298

Step-by-step explanation:

Since C is a right angle, when the circle is circumscribed it will be an inscribed angle with a corresponding arc length of 2*90=180 degrees. This means that AB is the diameter of the circle. Since the cosine of an angle in a right triangle is equivalent to the length of the adjacent side divided by the length of the hypotenuse:

\cos 38= \dfrac{8}{AB} \\\\\\AB=\dfrac{8}{\cos 38}\approx 10.152

To find the area of the circumscribed circle:

r=\dfrac{AB}{2}\approx 5.076 \\\\\\A=\pi r^2\approx 80.95

To find the area of the inscribed circle, you need the length of AC, which you can find with the Pythagorean Theorem:

AC=\sqrt{10.152^2-8^2}\approx 6.25

The area of the triangle is:

A=\dfrac{bh}{2}=\dfrac{8\cdot 6.25}{2}=25

The semiperimeter of the triangle is:

\dfrac{10.152+6.25+8}{2}\approx 24.4

The radius of the circle is therefore \dfrac{25}{24.4}\approx 1.025

The area of the inscribed circle then is \pi\cdot (1.025)^2\approx 3.298.

Hope this helps!

6 0
3 years ago
A car traveling at 35mph follows a/an ____________ pattern.
zheka24 [161]

Answer:

C. Exponential

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A speed limit is 35 mph. A car is travelling 10 mph over the speed limit. I’d that a sum of 0
max2010maxim [7]

Answer:

The car is going 45 mph

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(hope this helped)

5 0
3 years ago
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