Answer:
We are effectively looking for a and b such that 5, a, b, 135 is a geometric sequence.
This sequence has common ratio <span><span>3<span>√<span>1355</span></span></span>=3</span>, hence <span>a=15</span> and <span>b=45</span>
Explanation:
In a geometric sequence, each intermediate term is the geometric mean of the term before it and the term after it.
So we want to find a and b such that 5, a, b, 135 is a geometric sequence.
If the common ratio is r then:
<span><span>a=5r</span><span>b=ar=5<span>r2</span></span><span>135=br=5<span>r3</span></span></span>
Hence <span><span>r3</span>=<span>1355</span>=27</span>, so <span>r=<span>3<span>√27</span></span>=3</span>
Then <span>a=5r=15</span> and <span>b=ar=15⋅3=45</span>
Answer:
x > 73
Step-by-step explanation:
x+7 > 80
subtract 7 from both sides
x + 7 - 7 > 80 - 7
x > 73
-Chetan K
The answer is 6m djsjdjjsskskksksksksksksmsmsm
Answer:
3^2, 9 students.
Step-by-step explanation:
I'm not 100 percent sure about this but I'm pretty sure that because there are 3 rows you can just do 3^2 which is 9.
