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AysviL [449]
3 years ago
7

PLEASE HELP THIS IS VERY IMPORTANT I'LL GIVE YOU BRAIN THING IF ITS CORRECT!! <3 NO LINKS PLEASEE.

Mathematics
1 answer:
Nataly_w [17]3 years ago
7 0

Answer and Step-By-Step Explanation:

The point shown is marked at (36,82), meaning that the panda is 36 months old and weighs 82 kilograms.  To plot the next point, just go up from 110 on the graph to 90 and mark a point.  (Sorry I tried to put an image but it was extremly blurry.)

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Write a rule for the nth term of the sequence. Then find a20. Assume the first termis a₁. 86, 79, 72, 65…
hodyreva [135]

Answer:

an = a(n-1) - 7

Step-by-step explanation:

the second term is smaller than the first term 7.

a20 = a19 - 7

a19 = a18 - 7

=> a20 = (a18 - 7) - 7

Then you can accumalate until a1

-> a20 = a1 - 19*7 = 86 - 19*7 = -47

5 0
2 years ago
Find how many six-digit numbers can be formed from the digits 2, 3, 4, 5, 6 and 7 (with repetitions), if:
Goshia [24]

Answer:

case 1 = 2592

case 2 =  729

case 1 + case 2 =  2916

(this is not a direct adition, because case 1 and case 2 have some shared elements)

Step-by-step explanation:

Case 1)

6 digits numbers that can be divided by 25.

For the first four positions, we can use any of the 6 given numbers.

For the last two positions, we have that the only numbers that can be divided by 25 are numbers that end in 25, 50, 75 or 100.

The only two that we can create with the numbers given are 25 and 75.

So for the fifth position we have 2 options, 2 or 7,

and for the last position we have only one option, 5.

Then the total number of combinations is:

C = 6*6*6*6*2*1 = 2592

case 2)

The even numbers are 2,4 and 6

the odd numbers are 3, 5 and 7.

For the even positions we can only use odd numbers, we have 3 even positions and 3 odd numbers, so the combinations are:

3*3*3

For the odd positions we can only use even numbers, we have 3 even numbers, so the number of combinations is:

3*3*3

we can put those two togheter and get that the total number of combinations is:

C = 3*3*3*3*3*3 = 3^6 = 729

If we want to calculate the combinations togheter, we need to discard the cases where we use 2 in the fourth position and 5 in the sixt position (because those numbers are already counted in case 1) so we have 2 numbers for the fifth position and 2 numbers for the sixt position

Then the number of combinations is

C = 3*3*3*3*2*2 = 324

Case 1 + case 2 = 324 + 2592 = 2916

4 0
3 years ago
The school that Lisa goes to is selling tickets to the annual talent show. On the first day of ticket sales the school sold 4 se
kakasveta [241]
Let:
x = cost of senior citizen ticket
y = cost of student ticket

4x + 5y = 102
7x + 5y = 126

4x + 5y = 102
4x = 102 - 5y
x = (102 - 5y)/4
x = 102/4 - 5y/4

7x + 5y = 126
7(102/4 - 5y/4) + 5y = 126
(714/4 - 35y/4) + 5y = 126
-35y/4 + 5y = 126 - 714/4

note:
-35y/4 = -8.75y
714/4 = 178.5

-8.75y + 5y = 126 - 178.5
-3.75y = -52.5
y = -52.5/-3.75
y = 14


x = 102/4 - 5y/4
x = 102/4 - 5(14)/4
x = 8

x = cost of senior citizen ticket = $8/ea
y = cost of student ticket = $14/ea



6 0
3 years ago
What is 1 6/8 of 16
NARA [144]

Answer:

I'm pretty sure its 28?

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help due today
vekshin1
The answer is 21 m squared
3(5)=15
3(2)=6
15+6=21
5 0
2 years ago
Read 2 more answers
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