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8_murik_8 [283]
4 years ago
7

On a sine function y = Asin(Bx) +C , the maximum value is 19 and the minimum value is -5. Which of the following must be the val

ue of |A| - C ?
Mathematics
1 answer:
blagie [28]4 years ago
5 0

Answer:

|A| - C = 5

Step-by-step explanation:

The maximum value that a sine function can have is 1, and the minimum value is -1.

With this information, to find the minimum value of y, we can use sin(Bx) = -1, and to find the maximum value, we can use sin(Bx) = 1. Then, we have that:

19 = A + C

-5 = -A + C

Summing both equations, we have:

14 = 2C

C = 7

Now, to find the value of A, we can use the first equation:

19 = A + C

19 = A + 7

A = 12

So the value of |A| - C is:

|12| - 7 = 12 - 7 = 5

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What two numbers add to -7 and multiply to -60
Cloud [144]

Answer:

The answer would be 5 and -12

5 0
3 years ago
Sendo A = (-1, 0, 1, 2) e B = (-2, -1, 0, 1, 2, 3, 4), verifique em cada caso se a lei dada define uma função de A com valores e
Eduardwww [97]

Answer:

A

Step-by-step explanation:

Because f(x) equals 4X

8 0
3 years ago
The shorter sides of an acute triangle are x cm and 2x cm. The longest side of the triangle is 15 cm. What is the smallest possi
Veronika [31]

The longest side in the triangle is opposite to the largest angle of this triangle. If triangle is acute, then all angles are acute. Acute angle has cosine that is positive.

Use cosine theorem to determine the cosine of the largest angle:

15^2=x^2+(2x)^2-2\cdot x\cdot 2x\cdot \cos \alpha, where \alpha is the largest angle.

Then

225=x^2+4x^2-4x^2\cos \alpha,\\ \\\cos \alpha=\dfrac{225-5x^2}{-4x^2}=\dfrac{5x^2-225}{4x^2}.

Since \cos \alpha>0, then

\dfrac{5x^2-225}{4x^2}>0\Rightarrow 5x^2-225>0.

Divide this inequality by 5:

x^2-45>0,\\ \\(x-3\sqrt{5})(x+3\sqrt{5})>0,\\ \\x\in (-\infty,-3\sqrt{5})\cup (3\sqrt{5},\infty).

Note that 3\sqrt{5}\approx 6.71, then the smallest possible whole-number value of x is 7.

Answer: correct choice is B

6 0
3 years ago
Read 2 more answers
THIS QUESTION IS NOT AVALIBLE ANYMORE.<br><br>You can use this now for points.
Alekssandra [29.7K]

Thanks for the points?

4 0
3 years ago
Since there are 12 tenths you need to regroup. you can regroup 12 tenths as 1 whole and 2 tenths
Effectus [21]
1 whole, 1 tenth, 10 ones = 12 tenths
6 0
3 years ago
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