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wariber [46]
3 years ago
14

A phone company charges $0.06 per minute for local calls and $0.15 per minute for international calls. When your bill comes, it

states that you accumulated 852 minutes with a charge of $69.84. Write and solve a system of linear equations to find the number of local and international minutes used.
Mathematics
1 answer:
iragen [17]3 years ago
7 0
Let
 x = number of minutes of local calls.
 y = number of minutes of international calls.
 By writing the system of equations we have:
 0.06x + 0.15y = 69.84
 x + y = 852
 Solving the system
 Clear y from equation two
 y = 852-x
 Replace y in equation 1
 0.06x + 0.15 (852-x) = 69.84
 Clear x
 0.06x + 127.8 - 0.15x = 69.84
 127.8 - 69.84 = 0.15x -0.06x
 57.96 = 0.09x
 x = 57.96 / 0.09 = 644
 x = 644
 Replace x in any of the two equations and clear y:
 x + y = 852
 y = 852-644
 y = 208
 answer
 number of minutes of local calls = 644
 number of minutes of international calls = 208
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M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)

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M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)

\Rightarrow E\left(X^{2}\right)=\frac{91}{6}  

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(b) \mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}

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4 years ago
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