Answer:
slope: -1/3
you find the slope by taking one point (0,2) and then finding the change in y over the change in x from it to another point (3,1) :
1-2/(3-0) = -1/3
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
Step-by-step explanation:
To find the slope, rearrange the equation to y=mx+b or y=mx+c.
Subtract 4x from both sides:
Divide 5 on both sides:
In the equation of y=mx+b/y=mx+c, m will be the slope.
Therefore, the slope is
Answer:
Plot (-9,5) then you do rise over run and go down 2 and to the right 3
Step-by-step explanation:
So your points would be (-9,5) and(-6,3)
Answer:
Step-by-step explanation:
