Which of the following correctly compares the uses of bar graphs versus pie charts? bar graphs show patterns in data with variab
les that change over time; whereas, pie charts show data as parts out of a whole (such as out of 100%). bar graphs show data as parts out of a whole (such as out of 100%) within a category; whereas, pie charts show data having two or more different categories. bar graphs show data involved in distinct categories that do not overlap; whereas, pie charts show data as parts out of a whole (such as out of 100%). bar graphs show data involved in distinct categories that do not overlap; whereas, pie charts show patterns in data with variables that change over time.
1 answer:
Answer:
<h3><em>Bar graphs show data involved in distinct categories that do not overlap; whereas, pie charts show data as parts out of a whole (such as out of 100%).</em></h3>Step-by-step explanation:
A bar graph, also called a bar chart, is used to present categorical variables, which involves rectangular bars with a correlation between a specific category and the frequency of them, this graphs can be also called histograms. It's used in statistics to describe a bunch a data, separating them in categories. This charts can be horizontal or vertical, and an important characteristics is that it's applied to represent discrete categories, that is, values expressed with whole numbers. (An example is attached).
On the other hand, pie charts, or circular charts, are used to indicate proportions from a whole part, like a pie or cake, you have a whole and 100% data and you divided into slices. For example, from the whole population in the U.S. we could divide it by ethnicity, parts from a whole, like show the image attached.
<h3>Therefore, based on each definition, the correct answer is:</h3><em>Bar graphs show data involved in distinct categories that do not overlap; whereas, pie charts show data as parts out of a whole (such as out of 100%).</em>
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Answer:
Probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Step-by-step explanation:
We are given that the diameters of ball bearings are distributed normally. The mean diameter is 106 millimeters and the standard deviation is 4 millimeters.
<em>Firstly, Let X = diameters of ball bearings</em>
The z score probability distribution for is given by;
Z = ~ N(0,1)
where, = mean diameter = 106 millimeters
= standard deviation = 4 millimeter
Probability that the diameter of a selected bearing is greater than 111 millimeters is given by = P(X > 111 millimeters)
P(X > 111) = P( >
) = P(Z > 1.25) = 1 - P(Z
1.25)
= 1 - 0.89435 = 0.1056
Therefore, probability that the diameter of a selected bearing is greater than 111 millimeters is 0.1056.
Answer:
4.3
Step-by-step explanation:
Apply trigonometric ratios to find the answer.
Firstly, we need to find the measure of angle theta. In order to do this, we will use triangle BAD.
From angle theta, the trigonometric ratio sine can be used:
sinθ =
After we find the value, we take the inverse sine of it and the result is approximately 50.7 degrees.
Now, knowing that angles BAD and CAD are the same, we can solve for CD using trigonometric ratio sine.
sin50.7 = opposite/hypotenuse
sin50.7 = CD/5.5
sin50.7 * 5.5 = CD
4.3 ≈ CD