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seraphim [82]
3 years ago
8

...Help Please...question in the file.

Mathematics
1 answer:
Snezhnost [94]3 years ago
7 0
3^{-3}= \frac{1}{3^3}= \frac{1}{27}   \\  \\ 3^{-2}= \frac{1}{3^2}= \frac{1}{9}   \\ \\ 3^{-1}= \frac{1}{3^1}= \frac{1}{3}   \\ \\3^{0}=1 \\\\ 3^1=3\\\\3^2=9\\\\3^3=27
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If ON= 5x - 7, LM = 4x+ 4, NM = x -7, and OL =3y-4, find the values of c and y for which LMNO MUST BE a parallelogram.
Sholpan [36]

Answer:

x=11, y=8/3

Step-by-step explanation:

Consider quadrilateral LMNO. If this quadrilateral MUST BE a parallelogram, then

LM=NO

and

LO=MN

Thus,

\left\{\begin{array}{l}4x+4=5x-7\\ \\x-7=3y-4\end{array}\right.

Solve this system of two equations. From the first equation:

4x-5x=-7-4\\ \\-x=-11\\ \\x=11

Substitute it into the second equation:

11-7=3y-4\\ \\3y-4=4\\ \\3y=4+4\\ \\3y=8\\ \\y=\dfrac{8}{3}

4 0
3 years ago
EASY MATH!!! GIVING BRAINLIEST!!!
Harman [31]
120 grams half life at 45 days would be 60 then half life of 60 in another 45 days (90 total) should be 30 grams
8 0
3 years ago
Can someone please helpp.
nika2105 [10]
1. Over a period of 6 years (from 1980 to 1986) the house gained a value of 12000 dollars (109k-97k). 12000/6 gives you a rate of 2000 dollars per year. Because the initial price at t=0 is 97000, the function is 97000+2000t
6 0
2 years ago
Ninety-one percent of products come off the line within product specifications. Your quality control department selects 15 produ
Allisa [31]

Answer:

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

Step-by-step explanation:

There is a random binomial variable X that represents the number of units come off the line within product specifications in a review of n Bernoulli-type trials with probability of success 0.91. Therefore, the model is {15 \choose x} (0.91) ^ {x} (0.09) ^ {(15-x)}. So:

P (X < 9) = 1 - P (X \geq 9) = 1 - [{15 \choose 9} (0.91)^{9}(0.09)^{6}+...+{ 15 \choose 15}(0.91)^{15}(0.09)^{0}] = 0.0002

P (X < 10) = 1 - P (X \geq 10) = 1 - [{15 \choose 10}(0.91)^{10}(0.09)^{5}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0013

P (X < 11) = 1 - P (X \geq 11) = 1 - [{15 \choose 11}(0.91)^{11}(0.09)^{4}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0082

P (X < 12) = 1- P (X \geq 12) = 1 - [{15 \choose 12}(0.91)^{12}(0.09)^{3}+...+{15 \choose 15} (0.91)^{15}(0.09)^{0}] = 0.0399

Probability of stopping the machine when X < 9 is 0.0002

Probability of stopping the machine when X < 10 is 0.0013

Probability of stopping the machine when X < 11 is 0.0082

Probability of stopping the machine when X < 12 is 0.0399

8 0
3 years ago
What is the fraction in a decimal form 8/50 ? Hellpppppp pllzzzz
Roman55 [17]

Answer: 0.16


Step-by-step explanation:

You can reduce this fraction

8/50

4/25 = 4 ÷ 25 = 0.16


I hope this helps! c:

6 0
3 years ago
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