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34kurt
4 years ago
6

If you have a test average of 92 and a standard deviation of 1.8, you generally do well on tests.

Mathematics
2 answers:
klasskru [66]4 years ago
8 0
I'm not sure if this is simply a true/false question but if so the answer is true.  With a standard deviation of 1.8, your tests would always remain in the A range.

Hope that helps.
MrRa [10]4 years ago
4 0
Is that it is think it is 118
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3x +15 = 2x + 10 + x + 5
Shkiper50 [21]

Answer:

The equation is true.

Step-by-step explanation:

Simplify. Combine like terms:

3x + 15 = (2x + x) + (10 + 5)

3x + 15 = (3x) + 15

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Subtract 3x and 15 from both sides:

3x (-3x) + 15 (-15) = 3x (-3x) + 15 (-15)

3x - 3x = 15 - 15

0 = 0

~ True. The two expressions are equal to each other.

~

4 0
3 years ago
Read 2 more answers
80g + 30h = 10(g + h)
vladimir2022 [97]

Assignment: \bold{Simplify \ Expression: \ 80g+30h=10\left(g+h\right)}

<><><><><><><>

Answer: \boxed{\bold{g=-\frac{2h}{7}}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Expand \bold{10\left(g+h\right): \ 10g+10h}

\bold{80g+30h=10g+10h}

[ Step Two ] Subtract 30h From Both Sides

\bold{80g+30h-30h=10g+10h-30h}

[ Step Three ] Simplify

\bold{80g=10g-20h}

[ Step Four ] Subtract 10g From Both Sides

\bold{80g-10g=10g-20h-10g}

[ Step Five ] Simplify

\bold{70g=-20h}

[ Step Six ] Divide Both Sides By 70

\bold{\frac{70g}{70}=\frac{-20h}{70}}

[ Step Seven ] Simplify

\bold{g=-\frac{2h}{7}}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

4 0
3 years ago
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alexgriva [62]
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patriot [66]

Answer:

C and D

Step-by-step explanation:

Kil represents one thousand, and milli represents one thousandth.

3 0
3 years ago
Determine whether each number is a solution of the
Yakvenalex [24]

Answer:

no

Step-by-step explanation:

as if the answer is 2 then the left hand side is less than the right and the equation states that the left is ment to be greater

5 0
3 years ago
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