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Gelneren [198K]
2 years ago
10

Pam and Erin are both planting gardens for their backyards. They want their gardens to be proportional. If pams garden has a len

gth of 16 feet and a width of 12 feet, what length does Erin need if the width of her garden is 21 feet?
Mathematics
1 answer:
Simora [160]2 years ago
8 0

Step-by-step explanation:

Pam and Erin want the gardens to be proportional.

<em>proprtional</em><em>-</em><em> </em><em>equal</em><em> </em>

Pams garden has a length of 16 and width of 12. To find the area of Pam's garden multiply the length by the width.

<em>16</em><em>×</em><em>12</em><em>=</em><em> </em><em>192</em><em> </em>

Now that we know the area of Pam's garden, we can set up and equation for Erin's garden. Since they have to be equal we know that Erin's garden should equal 192. Thus we solve for the length by dividing the width from the total.

<em>192</em><em>÷</em><em>21</em><em>=</em><em>9.14</em>

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At a local high school football game, 150 randomly selected people were surveyed about the location of the concession stand. 108
Nesterboy [21]

Answer:

Option B

<em>The best point estimate of the proportion of people attending the game who believe that the concession stand should be closer to the stands is:</em>

<em>p = 0.72.</em>

Step-by-step explanation:

We want to estimate the proportion of people who feel that the stand should be closer to the stands.

We have a sample of 150 people, of which 108 think that the stand should be closer to the stands.

A point estimator for the proportion p is p\¨.

Where

p\¨ = \frac{x}{n}

Where n represents the size of the sample and represents the number of favorable cases.

We know that n = 150 and x = 108.

Then we can estimate p by the estimator p\¨

p\¨= \frac{108}{150}

p\¨ = 0.72

4 0
3 years ago
Read 2 more answers
How many times greater is the value of the 4 in 64781 than the value of the 2 in 25409
HACTEHA [7]

64,781 --- 4,000

25,409 --- 400

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7 0
3 years ago
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Svetllana [295]
I would try b the rise\run is 2\2 so give it a go
8 0
3 years ago
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max2010maxim [7]
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The goal of a nutritional study was to compare the caloric intake of adolescents living in rural areas of the US with the calori
stiks02 [169]

Answer:

To give more clarity to the question, lets examine the attached back-to-back stem plot.

A)

Having examined the stem plot, we can using quick calculations, summarize that:

The mean (40.45 cal/kg) and median (41 cal/kg) daily caloric intake of ninth-grade students in the rural school is higher than the corresponding measures of center, mean (32.6 cal/kg) and median (32 cal/kg), for ninth-graders in the urban school.

The median and the mean for the students in the 9th grade in the urban school is lower than that of those of their contemporaries in the rural school. The respective medians and means are stated below:

Urban 9th Grade Students

Median = 32 cal/kg

Mean = 36 cal/kg

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Mean = 41 cal/kg

Please note that all figures above have been approximated to the nearest whole number.

B)

It is unreasonable to generalize the findings of this study to all rural and urban 9th-grade students in the United States because the sample is too small compared to the target population size.

To allow for generalization, they would have to collect and analyze more samples say from every state within America.

Cheers!

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