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Pavlova-9 [17]
3 years ago
11

A group of children were asked if they like eating cupcakes or brownies.

Mathematics
1 answer:
Korvikt [17]3 years ago
4 0

Answer:

It’s 0.30

Step-by-step explanation:

I took the test bro

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(3+x)+2x+5

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What go in the blank
s2008m [1.1K]

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inverse

Step-by-step explanation:

¬ is the symbol for not.  When we have not a  implies not b  we have a inverse

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JulsSmile [24]

Answer:

G represents sets of student appearing for GENERAL KNOWLEDGE  

M represents sets of student appearing for MATHS

S represents sets of student appearing for SCIENCE

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3 years ago
A bag contains different colored candies. There are 50 candies in the bag, 28 are red, 10 are blue, 8 are green and 4 are yellow
Mrrafil [7]

Answer:

\displaystyle \frac{54}{5405}.

Step-by-step explanation:

How many unique combinations are possible in total?

This question takes 5 objects randomly out of a bag of 50 objects. The order in which these objects come out doesn't matter. Therefore, the number of unique choices possible will the sames as the combination

\displaystyle \left(50\atop 5\right) = 2,118,760.

How many out of that 2,118,760 combinations will satisfy the request?

Number of ways to choose 2 red candies out a batch of 28:

\displaystyle \left( 28\atop 2\right) = 378.

Number of ways to choose 3 green candies out of a batch of 8:

\displaystyle \left(8\atop 3\right)=56.

However, choosing two red candies out of a batch of 28 red candies does not influence the number of ways of choosing three green candies out of a batch of 8 green candies. The number of ways of choosing 2 red candies and 3 green candies will be the product of the two numbers of ways of choosing

\displaystyle \left( 28\atop 2\right) \cdot \left(8\atop 3\right) = 378\times 56 = 21,168.

The probability that the 5 candies chosen out of the 50 contain 2 red and 3 green will be:

\displaystyle \frac{21,168}{2,118,760} = \frac{54}{5405}.

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3 years ago
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Answer:

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3 years ago
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