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DochEvi [55]
4 years ago
11

Plot the x- and y-intercepts to graph the equation. y = −1/2 x −3?

Mathematics
2 answers:
Slav-nsk [51]4 years ago
7 0

The x intercept is (-6,0) and the Y intercept is (0,-3)

Tju [1.3M]4 years ago
5 0

you would place your point at  (-6,0) for the X intercept

and you would place your other point at (0,-3) for the Y intercept


I really hope this helps dear :)

~Izzie

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Use the rule y = 6x to fill in the table with the missing number.
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Answer:

The value in missing place is 24

Step-by-step explanation:

Given rule is:

y = 6x

Here x is the input(independent variable) and y is the output(dependent variable)

The values for x are plugged in to find the output of the input.

As we know the rule,

For x = 4, the value of y will be:

y = 6(4)\\y = 24

Hence,

The value in missing place is 24

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Step-by-step explanation:

if you put in the numbers twice ill just ignore that.

If 149 is 35less than the original cost, add 35 for the original cost

The original cost was 184 dollars

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Nikki spent 2/5 of her birthday money on new shoes and 1/4 of her birthday money on a new headband.
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Answer:

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Luis deposited $300 into his bank account. He now has $4,564. Enter and solve an equation to find how much was in his account be
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If you are a dog lover, having your dog with you may reduce your stress level. Does having a friend with you reduce stress? To e
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The outlier of a dataset is a data element that is relatively far from the remaining data elements

  • <em>99 is an outlier of pet group</em>
  • <em>See attachment for the parallel box plots</em>

<u>(a) Prove that 99 is an outlier for Pet</u>

We have:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

n = 15

The quartiles positions are:

Q_1 = \frac{n + 1}{4}

Q_1 = \frac{15 + 1}{4}

Q_1 = \frac{16}{4}

Q_1 = 4th

Q_3 = Q_1 \times 3

Q_3 = 4th \times 3

Q_3 = 12th

So, we have:

Q_1 = 4th

Q_3 = 12th

From the pet group:

The data elements at the 4th and 12th positions are 68 and 79

So, we have:

Q_1 = 68

Q_3= 79

The lower and upper limits of the outlier are:

L = Q_1 - 1.5 \times (Q_3 - Q_1)

U = Q_3 + 1.5 \times (Q_3 - Q_1)

So, we have:

L = 68 - 1.5 \times (79 - 68)

L = 51.5

U = 79+ 1.5 \times (79 - 68)

U = 95.5

This means that data below 51.5 or above 95.5 are outliers.

<em>Hence, 99 is an outlier because 99 is greater than 95.5</em>

<u>(b) The parallel box plot</u>

The three groups are:

<em>Pets: 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99</em>

<em>Erlento: 88 80 80 81 92 87 88 81 82 80 87 92 87 80 82 </em>

<em>Alone: 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99</em>

<em />

See attachment for the parallel box plots

Read more about box plots and outliers at:

brainly.com/question/14940764

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3 years ago
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