Answer:
a) 7/4 b) 5 c) 2
Step-by-step explanation:
Logrithmic Rule for a and b
Let a, M, N be positive real numbers.
a)
logaM - logaN = loga(M/N)
log9(7) - log9(4) = log9 (7/4)
b)
logaM + logaN = logaMN
log2 (x) + log2(9) = log2(45)
x9=45
(x9)/9 = 45/9
x = 5
c)
Change of base formula.
logb(x)=logd(b)/logd(x)
x log6(5) = log6(25) divide each term by log6(5)
x log6(5) / log6(5) = log6(25) / log6(5) Cancel common factor log6(5)
x = log6(25) / log6(5)
x = log6(5^2) / log6(5)
Expand log6(5^2) by moving 2 outside the logarithm.
x = 2log6(5) / log6(5) cancel the like term log6(5)
x = 2
Answer:
f(- 2) = 1
Step-by-step explanation:
f(- 2) means what is the value of f(x) when x = - 2
From the table we can see that when x = - 2 f(x) = 1
Hence
f(- 2) = 1
If number of nickel = n
number of dimes = 3n
number of quarters = 2n
Amount of nickel = 5n
Amount of dimes = 30n
Amount of quaters = 50n
Total Amount = <span>5n + 30n + 50n = 510
In short, Your Answer would be Option C
Hope this helps!</span>
Answer:
0.3333333333333...........
Answer:
ln(5/3)
Step-by-step explanation:
The desired limit represents the logarithm of an indeterminate form, so L'Hopital's rule could be applied. However, the logarithm can be simplified to a form that is not indeterminate.
<h3>Limit</h3>
We can cancel factors of (x-1), which are what make the expression indeterminate at x=1. Then the limit can be evaluated directly by substituting x=1.
