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finlep [7]
3 years ago
13

what is 4757874558969845787745+587547854784587457887745.............. i did this for free points :) i am bored

Mathematics
2 answers:
ra1l [238]3 years ago
7 0
Thanks you’re very cool :D
prisoha [69]3 years ago
6 0

Answer:

Thanks man

Step-by-step explanation:

You might be interested in
Gum
yan [13]

Answer:

60 pieces

Step-by-step explanation:

The rate of pieces to packages is 15/1.

Multiply this rate by 4 to get the answer.

15 * 4 = 60

3 0
4 years ago
Read 2 more answers
everything 3 days seth goes to the grocery store his best friend brian goes 5 days on what day will they both go on to the store
7nadin3 [17]
Wednesday??????????????????????????????????????
3 0
3 years ago
Who is correct and why?
Deffense [45]
There is no information below to give an answer .
6 0
4 years ago
Find two positive real numbers whose product is a maximum. the sum is 80
Eduardwww [97]
Let's say the numbers are "a" and "b"

thus \bf y=ab\qquad 
\begin{cases}
a+b=80\\
b=80-a
\end{cases}\implies y=a(80-a)\implies y=80a-a^2\\\\
-----------------------------\\\\
\cfrac{dy}{da}=80-2a

set the derivative to 0, and check the critical points, there's only one anyway

and do a first-derivative test, to see if it's a maximum
4 0
3 years ago
Read 2 more answers
(1.1/1.2: Interpolating polynomials) Say we want to find a polynomialf(x) ofdegree 3,f(x) =a0+a1x+a2x2+a3x3,satisfying some inte
Hunter-Best [27]

(a) If

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then from the given conditions we get the system of equations,

<em>f</em> (-1) = <em>a</em>₀ - <em>a</em>₁<em> </em>+<em> a</em>₂ - <em>a</em>₃ = -1

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+ 4<em>a</em>₂ + 8<em>a</em>₃ = 1

<em>f</em> (3) = <em>a</em>₀ + 3<em>a</em>₁<em> </em>+<em> </em>9<em>a</em>₂ + 27<em>x</em> ³ = 5

(b) Similarly, if

<em>f(x)</em> = <em>a</em>₀ + <em>a</em>₁ <em>x </em>+<em> a</em>₂ <em>x</em> ² + <em>a</em>₃ <em>x</em> ³

then

<em>f'(x)</em> = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ <em>x</em> + 3<em>a</em>₃ <em>x</em> ²

so that the given conditions yield the system,

<em>f</em> (1) = <em>a</em>₀ + <em>a</em>₁<em> </em>+<em> a</em>₂ + <em>a</em>₃ = 0

<em>f'</em> (1) = <em>a</em>₁<em> </em>+<em> </em>2<em>a</em>₂ + 3<em>a</em>₃ = 2

<em>f</em> (2) = <em>a</em>₀ + 2<em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 27<em>a</em>₃ = 3

<em>f'</em> (2) = <em>a</em>₁<em> </em>+<em> </em>4<em>a</em>₂ + 12<em>a</em>₃ = -1

7 0
3 years ago
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