Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.
Given:
Perimeter of the floor of a room = 18 metre
Height of the room = 3 metre
To find:
The area of 4 walls of the room.
Solution:
We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.
The curved surface area of the cuboid is

Where, h is height, l is length and b is breadth.
Perimeter of the rectangular base is 2(l+b). So,

Putting the given values, we get


Therefore, the area of 4 walls of the room is 54 sq. metres.
You would use the function root(Xsub2-Xsub1)^2+(Ysub2-Ysub1)^2.
Now plug in your numbers.
This gives you root(7-1)^2+(5-(-3))^2.
Simplify to root(6)^2+(8)^2. Simplify again to root36+64.
Simplify one more time to root 100. now solve.
Your answer is 10.
Answer: 6
Step-by-step explanation:
You would divide the number by the other number to get the awnser
Answer:
The answer is 19
Step-by-step explanation: 13 scored from 91-100, and 6 scored from 81-90, all you have to do is add them together.