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olchik [2.2K]
3 years ago
15

A researcher is conducting an experiment to test a new vitamin supplement. The researcher has recruited 8

Mathematics
1 answer:
Tju [1.3M]3 years ago
4 0

Answer:

(C) 32

Step-by-step explanation:

This is a problem of Permutation and Combination, not probability.

This clarification is given because most questions like this are on Probability and Statistics.

The researcher has recruited 8  participants and must divide them into two groups of 4 people each.

So there's:

GROUP A - Placebo Group

GROUP B - Experimental Group

Since the experiment is on humans - distinct objects - they will have distinct identities. Assume the 8 participants are lined up according to identities 1,2,3,4,  5,6,7,8

[2+2+2+2  +2+2+2+2] × 2 = 16×2 = 32

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A. we use the z statistic to solve this problem

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We calculate the value of the sample mean u and standard deviation s:

u = $30 * 304 = $9120

s = $21 * 304 = $6384

 

z = (9,600 – 9120) / 6384

z = 0.075

 

From the normal tables using right tailed test,

P = 0.47

 

B. At worst 11% means P = 0.11, so the z value at this is z = -1.23

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x = 1267.68

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4 years ago
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Answer:

a) P = 2/7

b) P = 4/7

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In the range of [2,8], we have the following integers which are: 2, 3, 4, 5, 6, 7, 8. So this is a total of 7 integers.

a) We look for the probability that the numbers are less than 4, so we conclude that there are possible numbers 2 and 3 out of possible 7, so the required probability is equal to P = 2/7.

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