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svp [43]
3 years ago
10

The delivery ramp at the corner cafe id a right triangle. The hypotenuse is 4 meters long. One leg is 3 meters long. What is the

length of the other leg
f. sqrt 7 meters
g. sqrt 12 meters
h. 3.5 meters
j. 5 meters
Mathematics
2 answers:
disa [49]3 years ago
7 0

Answer:

f. sqrt 7 meters

Step-by-step explanation:

we use Pythagoras' theorem here,

let the unknown side be x,

therefore,

=> 3² + x² = 4²

=> x² = 16 - 9

=> x = √7 m

Kruka [31]3 years ago
6 0

Answer:

f. sqrt 7 meters

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem to solve.  We know the hypotenuse is 4 and one leg is 3.  We want to solve for the other leg.

a^2 +b^2 = c^2  where a and b are the legs and c is the hypotenuse.

Substituting into the equation

3^2 + b^2 = 4^2

9+b^2 = 16

Subtracting 9 from each side

9-9+b^2 = 16-9

b^2 =7

Taking the square root of each side

sqrt(b^2) = sqrt(7)

b = sqrt(7) meters

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The soccer team played 7 games and scored the following number goals in each game: 2, 1, 3, 5, 3, 1, 4. What was the median numb
soldi70 [24.7K]
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6 0
2 years ago
Read 2 more answers
The diagram shows a circle, centre O.<br> Work out the value of a. <br> BCO=41 degrees
sattari [20]

Answer:

a = 49°

Step-by-step explanation:

OB = OC ( both radii of the circle ), thus

Δ BOC is isosceles and the base angles are congruent, that is

∠ OBC = ∠ OCB = 41° , so

∠ BOC = 180° - (2 × 41)° = 180° - 82° = 98°

The angle on the circumference BAC is half the angle at the centre for angles subtended on the same arc , thus

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5 0
3 years ago
Situation:
Gala2k [10]

Answer:

5.5 days (nearest tenth)

Step-by-step explanation:

<u>Given formula:</u>

\sf N=N_0e^{-kt}

  • \sf N_0 = initial mass (at time t=0)
  • N = mass (at time t)
  • k = a positive constant
  • t = time (in days)

Given values:

  • \sf N_0 = 11 g
  • k = 0.125

Half-life:  The <u>time</u> required for a quantity to reduce to <u>half of its initial value</u>.

To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:

\begin{aligned}\sf N & = \sf N_0e^{-kt}\\\\\implies \sf \dfrac{11}{2} & = \sf 11e^{-0.125t}\\\\\sf \dfrac{1}{2} & = \sf e^{-0.125t}\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf \ln e^{-0.125t\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t \ln e\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t(1)\\\sf t & = \sf \dfrac{\ln \left(\dfrac{1}{2}\right)}{-0.125}\\\\\sf t & = \sf 5.545177444...\\\\\sf t & = \sf 5.5\:\:days\:\:(nearest\:tenth)\end{aligned}

Therefore, the substance's half-life is 5.5 days (nearest tenth).

Learn more about solving exponential equations here:

brainly.com/question/28016999

5 0
2 years ago
Read 2 more answers
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