For a smoothing constant of 0.2
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 55.6 55.48 52.18 50.15 52.72 52.97 53.38 54.90
Forecast error - -12 -.6 -16.48 – 10.12 12.85 1.28 2.03 7.62 -2.9
The mean square error is 84.12
The mean forecast for period 11 is 54.38
For a smoothing constant of 0.8
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 48.40 53.68 41.94 41.99 58.80 54.96 54.99 59.80
Forecast error - -12 6.60 -14.68 0.06 21.01 -4.80 0.04 6.01 -7.80The mean square error is 107.17
The mean forecast for period 11 is 53.56
Based on the MSE, smoothing constant of .2 offers a better model since the mean forecast is much better compared to the 53.56 of the smoothing constant of 0.8.
Answer:
the answer is H. it's slope is 5/4 which is the opposite reciprocal of -4/5 and that makes the lines perpendicular.
Answer:no
Step-by-step explanation:
Because on a graph (2,3) means that the point is two along and three up while (3,2) means it is 3 along and two up.
X = 1/2 y = 4 by elimination
Answer:
or 6.32
Step-by-step explanation:
We can find the distance between two points by using this formula
where the x and y values are derived from the given points
The points given are ( -2 , 5 ) and ( 4 , 3 )
So we plug in the x and y values of those coordinates into the distance formula
or 6.32
